Answer:
2.1 mol
Explanation:
68.1g / 34.1 g/mol = 2.1mol
Mass of methane takne = 1.5g
moles of methane used = masss / molar mass = 1.5 / 16 = 0.094 moles
mass of water = 1000 g
Initial temperature of water = 25 C
final temperature = 37 C
specific heat of water = 4.184 J /g C
1) Heat absorbed by water = q =m• C• ΔT = 1000 X 4.184 x (37-25) = 50208 Joules
2) Heat absorbed by calorimeter = Heat capacity X ΔT = 695 X (37-25) = 8340 J
3) Total heat of combustion = heat absorbed by water + calorimeter = 50208 + 8340 = 58548 Joules
This heat is released by 0.094 moles of methane
So heat released by one mole of methane =
- 622851.06 Joules = 622.85 kJ / mole
4) standard enthalpy of combustion = -882 kJ / mole
Error = (882-622.85) X 100 / 882 = 24.84 %
Answer:
Fossil record
Explanation:
but first think about it befor you do so it could be wrong im not a computer
Answer:
H2 + O2
Explanation:
H2 + O2 --> H2O
The items on the left side is the reactants. The arrow means yields, and the item the arrow is pointing at is the product.
Answer:
cornell noted
Explanation:
used in middle school and can be helpful for subjects like ela history and science
