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Iteru [2.4K]
3 years ago
8

25, 8, 10, 35, 5, 45, 40, 30, 20

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0
B.) 37.5.. First you place all the numbers in order from least to greatest. Your mean is 25...and ur upper quartile because the 4 #'s fall even u add 35 and 40 and divide by 2... Which gives u upper quartile of 37.5 and lower quartile of 9. Hope this helps :)
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I’ve been stressing over this problem can anyone help how my answer would be 1
Kazeer [188]

Answer:

29° + (x - 5)° = 180°

29 + x - 5 = 180

29 - 5 + x = 180

24 + x = 180

24 - 24 + x = 180 - 24

x = 156

Step-by-step explanation:

A straight line is 180°.

Set all angles (29° and (x - 5)°) equal to 180°.

Then solve for x.

3 0
3 years ago
Read 2 more answers
what is the equation for “the product of a number and 3 is 5 less than the quotient of a number and 4
marishachu [46]
Equation 1.
20÷4=5
0×3=0
5-5=0
Equation 2.
44÷4=11
2×3=6
11-5=6
Equation 3.
56÷4=14
3×3=9
14-5=9
5 0
3 years ago
0.68 = 0.6 + ___ = ____ x 0.1 + 8 x ____
8_murik_8 [283]

0.68 = 0.6 + .08 = 6 x 0.1 + 8 x .01

They should all equal  0.68  :)

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C
MariettaO [177]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;

\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}

\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}

\qquad \sf  \dashrightarrow  \:m =  - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)

\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~

\qquad \sf  \dashrightarrow \:y =  - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :

\qquad \sf  \dashrightarrow \:y <  - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0
2 years ago
Por favor ayudenme a resolverlo
alukav5142 [94]
I dont know that language
6 0
3 years ago
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