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Orlov [11]
4 years ago
7

Bode's Law: correctly predicted the location of Jupiter, uses a number sequence to determine planetary distances, incorrectly pr

edicted the location of Uranus and Neptune, all of the above
Physics
1 answer:
nexus9112 [7]4 years ago
4 0
The correct answer for the question that is being presented above is this one: "correctly predicted the location of Jupiter, uses a number sequence to determine planetary distances." Bode's law <span>correctly predicted the location of Jupiter, uses a number sequence to determine planetary distances.</span>
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A spring has a equilibrium length of 10.0 cm. When a force of 40.0 N is applied to the spring, the spring has a length of 14.0 c
mote1985 [20]

Answer:

The value of the spring constant of this spring is 1000 N/m

Explanation:

Given;

equilibrium length of the spring, L = 10.0 cm

new length of the spring, L₀ = 14 cm

applied force on the spring, F = 40 N

extension of the spring due to applied force, e = L₀ - L = 14 cm - 10 cm = 4 cm

From Hook's law

Force applied to a spring is directly proportional to the extension produced, provided the elastic limit is not exceeded.

F ∝ e

F = ke

where;

k is the spring constant

k = F / e

k = 40 / 0.04

k = 1000 N/m

Therefore, the value of the spring constant of this spring is 1000 N/m

7 0
3 years ago
Look at the diagram below. From the frame of reference of the person riding
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There's no digram because I'm mr lemonade mr French fries
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3 years ago
Not a question, but I need help on the last two questions I posted, preferably no links, please...
Andrei [34K]

Answer:

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Explanation:

7 0
3 years ago
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A planet has a gravitational acceleration on its surface of 2.2 times Earth's gravitational acceleration on its surface. The pla
lesantik [10]

Answer:

The mass of the planet is 55 times the mass of earth.

Explanation:

From the inverse-square gravitation law,

F = (GMm/r²)

If the weight of a body (the force with which the earth attracts a body to its centre) is to be calculated,

F = mg

m = mass of the body,

g = acceleration due to gravity

mg = (GMm/r²)

G = Gravitational constant

M = mass of the earth

m = mass of body

r = distance between the body and the centre of the earth = radius of the earth

The acceleration due to gravity is given by

g = (GM/r²)

Making the mass of the earth, the subject of formula

M = (gr²/G) (eqn 1)

So, the planet described,

Let the acceleration due to gravity on the planet be g₁

Mass of the planet be M₁

Radius of the planet be r₁

g₁ = 2.2g

r₁ = 5r

M₁ = ?

Note that the gravitational constant is the same for both planets.

So, we can write a similar expression for the planet's acceleration due to gravity

g₁ = (GM₁/r₁²)

Substituting all the parameters known in terms of their corresponding earth values

2.2g = [GM₁/(5r)²]

2.2g = [GM₁/25r²]

M₁ = (55gr²/G)

Recall the expression for the mass of the earth

M = (gr²/G)

M₁ = 55 M

The mass of the planet, in terms of Earth masses = 55M

The mass of the planet is 55 times the planet of earth.

Hope this Helps!!!

5 0
4 years ago
The acronym laser stands for light amplification by ____ emission of radiation
AleksAgata [21]
<span>light amplification by stimulated emission of radiation </span>
6 0
3 years ago
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