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3 years ago

7

Bode's Law: correctly predicted the location of Jupiter, uses a number sequence to determine planetary distances, incorrectly pr

edicted the location of Uranus and Neptune, all of the above

1 answer:

nexus9112 [7]3 years ago

4 0

The correct answer for the question that is being presented above is this one: "correctly predicted the location of Jupiter, uses a number sequence to determine planetary distances." Bode's law <span>correctly predicted the location of Jupiter, uses a number sequence to determine planetary distances.</span>

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You shake a bottle of soda and take off the cap. If the soda shoots out of the

kicyunya [14]

Answer:

A. 11.5 m

Explanation:

Given,

The initial velocity of the soda cap, u = 15 m/s

The soda bottle cap is projected vertically upwards,

Hence, the angle formed with the ground, Ф = 90°

The maximum height of the projectile is given by the formula,

$h_{max} =\frac{u^{2}sin^{2}\phi}{2g}$

Substituting the given values in the above equation

$h_{max} =\frac{15^{2}sin^{2}90}{2X9.8}$

= 11.5 m

Hence, the maximum height of the cap is h = 11.5 m

8 0

3 years ago

Someone places a chocolate bar near a working radar set that is used to locate ships and airplanes. Which best describes what is

Svetach [21]

Well the chocolate bar may melt at the heat of the machine but why is there a chocolate bar there in the first place is my question xD

3 0

3 years ago

A block weighting 400kg rests on a horizontal surface and support on top of it another block of weight 100kg placed on the top o

masha68 [24]

The horizontal force applied to the block is approximately 1,420.84 N

The known parameters;

The mass of the block, w₁ = 400 kg

The orientation of the surface on which the block rest, w₁ = Horizontal

The mass of the block placed on top of the 400 kg block, w₂ = 100 kg

The length of the string to which the block w₂ is attached, l = 6 m

The coefficient of friction between the surface, μ = 0.25

The state of the system of blocks and applied force = Equilibrium

Strategy;

Calculate the forces acting on the blocks and string

The weight of the block, W₁ = 400 kg × 9.81 m/s² = 3,924 N

The weight of the block, W₂ = 100 kg × 9.81 m/s² = 981 N

Let <em>T</em> represent the tension in the string

The upward force from the string = T × sin(θ)

sin(θ) = √(6² - 5²)/6

Therefore;

The upward force from the string = T×√(6² - 5²)/6

The frictional force = (W₂ - The upward force from the string) × μ

The frictional force, $F_{f2}$ = (981 - T×√(6² - 5²)/6) × 0.25

The tension in the string, T = $F_{f2}$ × cos(θ)

∴ T = (981 - T×√(6² - 5²)/6) × 0.25 × 5/6

Solving, we get;

$T = \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8} \approx 183.27$

$Frictional \ force, F_{f2} = \left (981 - \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8} \times \dfrac{\sqrt{6^2 - 5^2} }{6} \times 0.25 \right) \approx 219.92$

The frictional force on the block W₂, $F_{f2}$ ≈ 219.92 N

Therefore;

The force acting the block w₁, due to w₂ $F_{w2}$ = 219.92/0.25 ≈ 879.68

The total normal force acting on the ground, N = W₁ + $\mathbf{F_{w2}}$

The frictional force from the ground, $\mathbf{F_{f1}}$ = N×μ + $\mathbf{F_{f2}}$ = P

Where;

P = The horizontal force applied to the block

P = (W₁ + $\mathbf{F_{w2}}$ ) × μ + $\mathbf{F_{f2}}$

Therefore;

P = (3,924 + 879.68) × 0.25 + 219.92 ≈ 1,420.84

The horizontal force applied to the block, P ≈ 1,420.84 N

Learn more about friction force here;

brainly.com/question/18038995

3 0

2 years ago

Energy energy can be transferred from one form to another we use many Indrajeet Converse in our daily life observe carefully to

aleksandr82 [10.1K]

Answer:

Find the list below.

Explanation:

Energy conversion imply the transformation of energy from one form to another. Examples of these conversions in my home include the following:

1. Chemical energy stored in food is converted to mechanical energy used in working(example sweeping)

2. Chemical energy stored in batteries are used to produce sound energy from the radio.

3. Electrical energy flowing through the wires are used to provide heat energy from the heating device.

4. Electric energy stored in the fan is converted to kinetic energy.

5. Chemical energy stored in petrol is converted to mechanical and electrical energies in the generator.

6. Electric energy supplied by the electric gas cooker is used to generate thermal energy after heating water.

7. Electrical energy flowing through the wires supply light energy in the bulbs.

8. Electric energy is converted to light and sound energy in the televisions.

9. Light energy from the sun is converted to chemical energy in the plants at the garden.

10. Electric energy is converted to sound and light energy in the kitchen blender.

3 0

3 years ago

Suppose a yo-yo has a center shaft that has a 0.230 cm radius and that its string is being pulled.

Fofino [41]

Answer:

Part a)

$\alpha = 782.6 rad/s^2$

Part B)

$\omega = 587 rad/s$

Part c)

$a_t = 24.3 m/s^2$

Explanation:

Part a)

As we know that

$a = R \alpha$

so we will have

$a = 1.80 m/s^2$

$R = 0.230 cm$

$\alpha = \frac{a}{R}$

$\alpha = \frac{1.80}{0.230 \times 10^{-2}}$

$\alpha = 782.6 rad/s^2$

Part B)

Angular speed of the yo-yo

$\omega = \alpha t$

so we have

$\omega = 782.6 \times 0.750$

$\omega = 587 rad/s$

Part c)

Tangential acceleration is given as

$a_t = R \alpha$

$a_t = (3.10 \times 10^{-2})(782.6)$

$a_t = 24.3 m/s^2$

6 0

3 years ago