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valkas [14]
4 years ago
5

Car has negative acceleration. What information can you infer from this?

Physics
2 answers:
postnew [5]4 years ago
5 0

Answer:

Its D.

Explanation:

I took the quiz

e-lub [12.9K]4 years ago
4 0
The answer is D. When it is negative it means going down or back. In this case the acceleration is going down. So that means it's slowing down. Hope this helps, rate me please.
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When a guitar string is plucked, the guitar string oscillates as a result of waves moving through the string. The vibrations of
oksian1 [2.3K]

Answer:

Explanation:

Wave produced in string and waves produced in air are different . The only similarity is that their frequency are equal . Otherwise , no similarity . One is transverse ( on wire ) , the other is longitudinal ( air ) . Their velocities too are different .

velocity = wavelength x frequency

if frequency is constant

wavelength  ∝  velocity

wavelength is proportional to velocity . Since their velocities are different , their wavelength too will be different.

4 0
3 years ago
A fisherman is fishing from a bridge and is using a "44.0-N test line." In other words, the line will sustain a maximum force of
avanturin [10]

Answer:

(a) W= 44N

(b)W= 31.65 N

Explanation:

Data

T=44 N : Maximum force that the rope can withstand without breaking

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

(a)  We apply the formula (1) at constant speed , then, a=0

W: heaviest fish that can be pulled up vertically

∑F = 0

T-W =0  

W = T

W= 44N

(b)  We apply the formula (1) , a= 1.26 m/s²

W: heaviest fish that can be pulled up vertically

W= m*g

m= W/g

g= 9.8 m/s² : acceleration due to gravity

∑F = 0

T-W = m*a

T= W+(W/g)*a

44=W*(1+1/9.8)* (1.26 )

44= W* 1.39

W= 44/1.39

W= 31.65 N

7 0
4 years ago
Helpppp meeeee eee!! ​
jeka94

Answer: its a

Explanation: hope this help im sorry if its wrong

 

4 0
3 years ago
An airplane is heading due south at a speed of 430 km/h . A wind begins blowing from the northwest at a speed of 85.0 km/h (aver
Igoryamba

Answer:

It should fly 8° to west of south at 430km/h

Explanation:

According to the diagram. X components for both velocities must have the same magnitude in order to get the resultant velocity due south.

V_{w}*cos(45) = V_{A}*sin(\alpha )   Solving for α:

α = 8.03°

5 0
3 years ago
A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p
kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2

V(t) = V_0 + a * t,

Where y_0 its our initial height, V_0  our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

y(t) =  38 \frac{m}{s} * t - \frac{1}{2} g t^2

V(t) = 38 \frac{m}{s} - g * t

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

0 m = 38 \frac{m}{s} - g * t

and obtain:

t = 38 \frac{m}{s} / g

t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}

t = 3.9 s

Plugin this time on our first equation we find:

y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2

y=73.67 m

6 0
3 years ago
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