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4 years ago

A copy machine makes 44

1 answer:

6 0

44 per minute. 44 x 5 minutes = 220 copies. But you have have 30 seconds left, 30 is half a minute so you also split what the machine does in half which is 22. 220 +22= 242.
242 copies is my answer.

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PLZZZZ HELLLLPPPPP IF U DO U ARE MY HEROOOOO FR

Romashka-Z-Leto [24]

Answer: The second one

Step-by-step explanation:

7 0

3 years ago

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asambeis [7]

Answer:

The sum of 2 and the quotient of 3 and y

Step-by-step explanation:

The expression 2 + 3/y without any parentheses is evaluated as ...

2 + (3/y)

which is a sum. The first contributor to the sum is 2, and the second contributor is the quotient of 3 and y. (Usually, "the quotient of "a" and "b" means "a/b".)

Hence the answer shown above is a good description of the expression.

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3 years ago

Solve for X. 2y-4x=10

aalyn [17]

Answer:

y = 5 + 2x

Step-by-step explanation:

Simplifying

2y = 4x + 10

Reorder the terms:

2y = 10 + 4x

Solving

2y = 10 + 4x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '2'.

y = 5 + 2x

Simplifying

y = 5 + 2x

7 0

3 years ago

Casey has a small business making dessert baskets. She estimates that her fixed weekly costs for rent and electricity are $200.

lisov135 [29]

Answer:

a) Total weekly cost = $300

b) For Cassey to break even she has to sell 4 baskets

Step-by-step explanation:

Cost of electricity and rent in a week = $200

Cost of ingredients to make one dessert basket = $2.50

Total cost of making 40 dessert basket= 40*25

= $100

a) Cassey total cost in a week is $200 + $100

= $300

b) if each basket is sold at $25,the total selling price of 40 baskets will be $(25*40)

= $1000.

For Cassey to break even with the cost of production she has to sell y basket.

y = cost of producing 25 baskets / cost of selling 1 basket

y = 100/25

y = 4 baskets

5 0

3 years ago

Plssss help

Andre45 [30]

Answer:

A) $\displaystyle \frac{1}{77}$ .
B) $\displaystyle \frac{12}{77}$ .
C) $\displaystyle \frac{4}{11}$ .

Step-by-step explanation:

All marbles here are identical. Also, the question isn't concerned about the order in which the marbles are drawn. Thus, all calculations here shall be combinations rather than permutations.

How many ways to choose three out of six identical red marbles without replacement?

$\displaystyle _6C_3 = c(6, 3) = {6\choose 3} = 20$ .

Note that these three expressions are equivalent. They all represent the number of ways to choose 3 out of 6 identical items without replacement.

How many ways to choose three out of all the 6 + 10 + 6 = 22 marbles?

$\displaystyle _{22} C_{3} = 1540$ .

The probability of choosing three red marbles out of these 22 marbles will be:

$\displaystyle \frac{\text{Number of ways for choosing three out of six red marbles}}{\text{Number of ways to choose three out of 22 marbles}} = \frac{20}{1540} = \frac{1}{77}$ .

How many ways to choose two out of six identical red marbles without replacement?

$\displaystyle _6 C_2 = 15$ .

How many ways to choose one out of 10 + 6 = 16 non-red marbles?

$_{16} C_1=16$ .

Choosing two red marbles does not influence the number of ways of choosing a non-red marble. Both event happen and are independent of each other. Apply the product rule to find the number of ways of choosing two red marbles and one non-red marble out of the pile of 22.

$_6 C_2 \cdot _{16} C_1= 240$ .

Probability:

$\displaystyle \frac{240}{1540} = \frac{12}{77}$ .

Double check that the order doesn't matter here.

None of the marbles are red. In other words, all three marbles are chosen out of a pile of 10 + 6 = 16 white and blue marbles. Number of ways to do so:

$_{16} C_{3} = 560$ .

Probability:

$\displaystyle \frac{560}{1540}= \frac{4}{11}$ .

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4 years ago

Read 2 more answers