1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serggg [28]
3 years ago
8

Suppose that you walk 10mi express the distance in yards

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

1 mile = 1760 yds

Therefore, if we multiply 1760 by 10 we will get 10 miles in yards

1760 * 10 = <em>17600 yards</em>

Hope it was helpful and clear.

Cheers,

posledela3 years ago
6 0
^ yes I second that answer
You might be interested in
6. Find the corresponding angle. <br><br> options:
weqwewe [10]
Were in the same grade
6 0
2 years ago
What is the percent of 45/100?
myrzilka [38]
45/100 is 4,500% 2/5 is 40% 18/40 is 45% 15/25 is 60%
5 0
3 years ago
Diane received 300 votes in the election for student council president. That was 60% of the students who voted election. How man
VikaD [51]

Answer:

  500

Step-by-step explanation:

The problem statement tells you ...

  300 = 0.60×voters

Dividing by the coefficient of the variable gives ...

  300/0.60 = voters = 500

500 students voted in the election.

8 0
3 years ago
Read 2 more answers
According to the Centers for Disease Control, the probability that a randomly selected citizen of the United States has hearing
laila [671]
I think the answer is yes you can because they are both different things.

What I mean by that is that the United Stated as .151% of its people with hearing problems, and .093% with vision problems. So really adding them together just mixes it saying that .244% of people in the united states have either a vision or a hearing problem.

It doesn’t make it any more or any less people by adding them together. Therefore it’s not any more or any less probable to pick one or the other.

Hopes this helps.
5 0
3 years ago
Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both, in case
lozanna [386]

Answer:

0.3339 = 33.39% probability that both Dave and Mike will show up

Step-by-step explanation:

Probability of independent events:

If A and B are independent events, the probability of both happening at the same time is given by:

P(A \cap B) = P(A)P(B)

In this question:

Event A: Dave shows up.

Event B: Mike shows up.

Christine knows that there is a 47% chance that Dave will not show up and a 37% chance that Mike will not show up.

This means that P(A) = 1 - 0.47 = 0.53, P(B) = 1 - 0.37 = 0.63.

a. What is the probability that both Dave and Mike will show up

P(A \cap B) = P(A)P(B) = 0.53*0.63 = 0.3339

0.3339 = 33.39% probability that both Dave and Mike will show up

8 0
2 years ago
Other questions:
  • write the equation of a parallel to the given line and passing through the given point. y=-x+7; (7,1) I need the answer now plea
    14·1 answer
  • Let set A = {1,3,5,7} and set B = {1,2,3,4,5,6,7,8}
    14·1 answer
  • A strip of wood 78 inches long is to be cut into pieces 3 3/4 inches long. How many pieces can be cut?. . A. 12. B. 26. C. 20. D
    13·2 answers
  • Larry claims,( 14+12) x(8+12) and (14x12) +(8x12) are equivalent because they have the same digits and the same operations. Is L
    7·1 answer
  • Find the domain and range of the relation: (-3,9),(-3,8),(-3,7),(-3,6). Then determine whether the relation is a function.
    7·1 answer
  • Write the equation of a line that is parallel to y= -5/4x + 7 and that passes through the point (-4,1)
    6·1 answer
  • a pack of cinnamon scented pencils sells for $4.00. what is the sales tax rate if the total cost of the pencils is $4.32
    5·1 answer
  • 72/60<br> Write<br><br> in simplest form.
    9·2 answers
  • How many 1/3 of a hour to make a hour?
    8·1 answer
  • 4. What percent of all computers sold during the entire week<br><br> were sold on Friday!
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!