Across 5: predation
across 6 hominid
down 3 : Distribution
down 9 : glaciations
Answer:
50% or 1/2. The result remains unchanged if the husband were to have G6PD.
Explanation:
For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.
Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype . A normal man will have the genotype . When the 2 marries:
x = It thus means that 50% or 1/2 of their sons will be expected to have G6PD.
Now, assuming the husband has G6PD, the mating becomes:
x = 50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.
Answer:
Explanation:
We recognize that total occurrence equals new cases of disease over time divided by the number of people at risk at the onset.
Mathematically:
Given that:
Number of the population at risk = 1000 individuals
New cases during Jan 1 - Dec 31 = 60 because;
At 20 occurred on June 30 & 40 on Sept. 30) & no new cases were identified after that:
∴
I would say the scientific method?