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3 years ago

Which of the following statements most accurately describes the difference between aptitudes and skills?

Computers and Technology

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

D. Aptitude is a person’s potential to learn new skills.

Explanation:

A. Aptitudes are ability, and skills are the potential.

B. Aptitudes can be learned or trained, unlike skills.

C. Aptitude is the level of skill that a person has gained.

D. Aptitude is a person’s potential to learn new skills.

Out of the above four, the A and B part is wrong and the rest of the options are right. Skills are the ability and aptitude is the potential, and the aptitude is the level of skill which person has gained, as well as Aptitude, is the Person's potential to learn new skills. However, D is adequate, and C can be derived out of it, as if someone has potential, the better level of skills he/she will gain. Hence, D is the correct option.

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Hotels and motels that are part of a ________ share a centralized reservation system and a common image, logo or advertising slo

hoa [83]

It is company , I think .

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3 years ago

Tracy has a file that contains a list of actors and the movies in which they acted. She wants to know the top 3 ranked actors fr

harina [27]

Answer:

{

private String name;

private String review;

/** Constructs a ProductReview object and initializes the instance variables. */

public ProductReview(String pName, String pReview)

{

name = pName;

review = pReview;

}

/** Returns the name of the product. */

public String getName()

{ return name; }

/** Returns the review of the product. */

public String getReview()

{ return review; }

}

The ReviewCollector class, shown below, is used to represent a collection of reviews to be analyzed.

public class ReviewCollector

{

private ArrayList<ProductReview> reviewList;

private ArrayList<String> productList;

/** Constructs a ReviewCollector object and initializes the instance variables. */

public ReviewCollector()

{

reviewList = new ArrayList<ProductReview>();

productList = new ArrayList<String>();

}

/** Adds a new review to the collection of reviews, as described in part (a). */

public void addReview(ProductReview prodReview)

{ /* to be implemented in part (a) */ }

/** Returns the number of good reviews for a given product name, as described in part (b). */

public int getNumGoodReviews(String prodName)

{ /* to be implemented in part (b) */ }

// There may be instance variables, constructors, and methods not shown.

}

3 0

4 years ago

By using password-stealing software, ________ capture what is typed on a keyboard and easily obtain enough personal information.

wariber [46]

Answer:

B) Keyloggers

Explanation:

Keyloggers are malicious softwares used by hackers to secretly record and capture keystrokes on a person's computer when they are using it. This enables the hackers steal sensitive data like passwords, bank details, address etc. Keyloggers are one of the oldest forms of cyber threats used by cybercriminals to spy on unsuspecting users. Keyloggers can be sent through links to access. computer o directly installed with access to the computer.

5 0

3 years ago

Type the correct answer in the box. Spell all words correctly. How is it possible to access data from any location? Storing data

romanna [79]

Answer:

optical

Explanation:

The earliest of these was the magnetic device. Computer systems began with magnetic storage in the form of tapes (yes, just like a cassette or video tape). These graduated to the hard disk drive and then to a floppy disk.

5 0

3 years ago

A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co

tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k ...(1)

probability of 2 hops = k(1-k) ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

= (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

= k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

∞ n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

n-1

= 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet = k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet = $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

6 0

3 years ago