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3 years ago

Which of the following statements most accurately describes the difference between aptitudes and skills?

Computers and Technology

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

D. Aptitude is a person’s potential to learn new skills.

Explanation:

A. Aptitudes are ability, and skills are the potential.

B. Aptitudes can be learned or trained, unlike skills.

C. Aptitude is the level of skill that a person has gained.

D. Aptitude is a person’s potential to learn new skills.

Out of the above four, the A and B part is wrong and the rest of the options are right. Skills are the ability and aptitude is the potential, and the aptitude is the level of skill which person has gained, as well as Aptitude, is the Person's potential to learn new skills. However, D is adequate, and C can be derived out of it, as if someone has potential, the better level of skills he/she will gain. Hence, D is the correct option.

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What is software and explain the five types of software

rewona [7]

Question: What is software and explain the five types of software

Explanation: The system software which is controlled and managed by the use of set of instructions and programs is called software.

Ex: Windows 7/8/10/xp etc...

the types of software are'

system software and application software

Android.

CentOS.

iOS.

Linux.

Mac OS.

MS Windows.

Ubuntu.

Unix.

5 0

3 years ago

Read 2 more answers

Suppose there are 69 packets entering a queue at the same time. Each packet is of size 7 MiB. The link transmission rate is 1.7

svp [43]

Answer:

69.08265412 milliseconds

Explanation:

Lets first convert 7 MiB to bits

$7*1024*1024*8=58720256$ bits

Now convert bits to Gbits

$58720256/10^{9} =0.058720256$ Gbits

Queuing Delay = Total size/transmission link rate

Queuing Delay= $\frac{0.058720256}{1.7} =0.03454132706$ seconds

Delay of packet number 3 = $0.03454132706*2=0.06908265412$ seconds

or $0.06908265412= 69.08265412$ milliseconds

7 0

3 years ago

Why should computers have a file structure? For organization For storing code To prevent viruses To keep back-ups of files

AURORKA [14]

Answer: I believe the answer to your question is For organization I hope this helps!

8 0

3 years ago

Meg[] elements = {new Lois(), new Stewie(), new Meg(), new Brian()}; for (int i =0; i

Stells [14]

Complete question is attached as snapshot.

Answer:

This will result in a compilation error.

Here's the inheritance hierarchy:

Meg -> Lois -> Brian -> Stewie

Now Meg has 2 public Fxns, a() and toString().

Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.

So finally Lois has fxns a(), b() and toString().

Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.

Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.

In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.

This results in a compilation error.

Explanation:

7 0

3 years ago

Java Eclipse homework. I need help coding this

olganol [36]

Answer:

I can't just do your project but use this as a head start.

Explanation:

public class TableOfBases

{

public static void main(String[] args)

{

// print out "Decimal Binary Octal Hex Character";

// write a for loop from 65 to 90

for (int i ... ) {

// get a string for integer i with base 2

String binary = Integer.toString (i,2);

// get a string for integer i with base 8

String octal = Integer.toString( ... );

// get a string for integer i with base 16

String hex = ...

// get a char for a chararater that has ASCII code i

char ch = (char) i ;

// print out binary, octal and hex, and ch

}

Project... Basically Speaking

Create a project called TableOfBases with class Tester.

The main method should have a for loop that cycles through the integer values

65 <= j <= 90 (These are the ASCII codes for characters A â€“ Z).

Use the methods learned in this lesson to produce a line of this table on each pass

through the loop. Display the equivalent of the decimal number in the various bases

just learned (binary, octal, and hex) as well as the character itself:

Decimal Binary Octal Hex Character

65 1000001 101 41 A

66 1000010 102 42 B

67 1000011 103 43 C

68 1000100 104 44 D

69 1000101 105 45 E

70 1000110 106 46 F

....

71 1000111 107 47 G 72 1001000 110 48 H 73 1001001 111 49 I 74 1001010 112 4a J 75 1001011 113 4b K 76 1001100 114 4c L 77 1001101 115 4d M 78 1001110 116 4e N 79 1001111 117 4f O 80 1010000 120 50 P 81 1010001 121 51 Q 82 1010010 122 52 R 83 1010011 123 53 S 84 1010100 124 54 T 85 1010101 125 55 U 86 1010110 126 56 V 87 1010111 127 57 W 88 1011000 130 58 X 89 1011001 131 59 Y 90 1011010 132 5a Z

7 0

3 years ago