Answer:
6
Step-by-step explanation:
You must find the least common multiple of their schedules.
The numbers 3 and 2 are their own prime factors, so the least common multiple of 3 and 2 is 6.
Six weekends must pass until they can both have someone over on the same night.
The number line below shows that the first time their sleepovers coincide is Week 6.
-4 > -5, -4 is > or equal to 5
There are various ways in which you could do this problem. I'm going to share what I think is one of the faster ways.
Instead of thinking of jumping from (-1,4) TO (2,-2), Consider the horiz. jump separately and the vertical jump separately. From -1 to 2 is 3 units. Three times that is 9 units. Add 9 to -1, obtaining 8. That's the horiz. component of the terminal point.
From 4 to -2 is -6 units. Mult. that by 3. The result is the vert. comp of the terminal point.
The answer is an Interval.
Hope this help.
The shortest possible height of tower is 24 cm.
Tim used 4 blue blocks and his brother used 3 green blocks.
Step-by-step explanation:
Given,
Height of blue block = 6 cm
Height of green block = 8 cm
We will take least common multiple to find the shortest possible height.
6 = 2*3
8 = 2*2*2
LCM = 2*2*2*3 = 24 cm
The shortest possible height of tower is 24 cm.
Number of blue blocks used = 
Number of green blocks used = 
Tim used 4 blue blocks and his brother used 3 green blocks.
Keywords: LCM, multiplication
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