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NeTakaya
3 years ago
6

Someone plss asnwer i need help amswer only if u know it​

Physics
2 answers:
My name is Ann [436]3 years ago
7 0

Answer:

going backwards message me if u have any problems

miv72 [106K]3 years ago
6 0

Answer:

slowing down

Explanation:

the opposite of positive is negative right?

so negative acceleration is deceleration

hope i helped!

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Suppose a candle is burning, and wind is blowing on one side of the flame. Which principle explains why the flame bends toward t
Mekhanik [1.2K]

When a candle is burning and wind is blowing it on one side of the flame, which causes the flame to bend towards the wind is an example of Bernoulli’s principle. The principle explain that the higher the speed, the lower the pressure becomes. When you blow against one side of the flame, you are creating an area of low pressure. The relatively high-pressure air on the other side of the candle will rush over to fill the area of low pressure that causes the flame to be pushed in the direction of the blowing.

4 0
3 years ago
If a car travels 30 kilometers in 2 hours, it’s average speed is?
7nadin3 [17]

Answer:

15km/h

Explanation:

Time taken to complete 30km/h=2 hours=15km/h hence the average speed is 15km/h.

5 0
3 years ago
Two parallel plates are a distance apart with a potential difference between them. A point charge moves from the negatively char
IgorC [24]

Answer:

K' = 1200 J

Explanation:

To find the kinetic energy you first take into account the formula for the kinetic energy of the charge:

K=\frac{1}{2}mv^2 = 800J   (1)

m: mass of the charge

v: final speed of the charge when it reaches the positively charged plate.

Furthermore, you have that the acceleration of the charge is obtained by using the second Newton law:

F=ma=qE\\\\a=\frac{qE}{m} (2)

a: acceleration

E: electric field

q: charge

The electric field between two parallel plates is V/d, being V the potential difference and d the separation between plates. You replace E in (2) and obtain:

a=\frac{qV}{md}

Next, you take into account the following formula for the calculation of the final speed of the charge:

v^2=v_o^2+2ad\\\\v_o=0m/s\\\\v=\sqrt{\frac{2qVd}{md}}=\sqrt{\frac{2qV}{m}}

Next, you replace this value of v in (1):

K=\frac{1}{2}mv^2=\frac{1}{2}m(\frac{2qV}{m})=qV = 880J   (3)

If the distance between plates is tripled, and the potential difference is halved, you have for the new final speed:

v'^2=v'_o^2+2a(3d)\\\\v_o=0m/s\\\\v'=\sqrt{6ad}=\sqrt{6(\frac{q}{md})\frac{V}{2}d}=\sqrt{\frac{3qV}{m}}

And the kinetic energy becomes:

K'=\frac{1}{2}mv^2=\frac{1}{2}m(\frac{3qV}{m})=\frac{3}{2}qV    (4)

You calculate the ratio between both kinetic energies K and K', that is, you divide equations (3) and (4), in order to find the new kinetic energy:

K=qV=800J\\\\K'=\frac{3}{2}qV\\\\\frac{K}{K'}=\frac{qV}{3/2\ qV}=\frac{2}{3}\\\\K'=\frac{3}{2}K=\frac{3}{2}(800J)=1200J

hence, the kinetic energy of the charge incresases to 1200J

4 0
3 years ago
A student (m = 68 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a
Gnesinka [82]

Answer:

5.7141 m

Explanation:

Here the potential and kinetic energy will balance each other

mgh=\frac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}

This is the initial velocity of the system and the final velocity is 0

t = Time taken = 0.04 seconds

F = Force = 18000 N

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}

From Newton's second law

F=ma\\\Rightarrow F=m\frac{v-u}{t}\\\Rightarrow 18000=68\frac{0-\sqrt{2gh}}{0.04}\\\Rightarrow \frac{18000}{68}\times 0.04=-\sqrt{2\times 9.81\times h}\\\Rightarrow 10.58823=-\sqrt{2\times 9.81\times h}

Squarring both sides

112.11061=2\times 9.81\times h\\\Rightarrow h=\frac{112.11061}{2\times 9.81}\\\Rightarrow h=5.7141\ m

The height from which the student fell is 5.7141 m

5 0
3 years ago
Two ladybugs are trapped in the front tire of Andy’s bicycle. He does not want to
timofeeve [1]

Answer:

as fast as he wants, ladybugs are useless

4 0
3 years ago
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