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RoseWind [281]
2 years ago
12

Identify the following joint

Physics
1 answer:
MissTica2 years ago
7 0

This is a ball and socket joint.

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1. What does the Work-Energy Theorem state?
Masja [62]
The principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle. ... Kinetic Energy: A force does work on the block. So the answer would be the first one.
5 0
3 years ago
Which sport was most interesting to you? Are there facilities in your community where you might be able to try one of these new
Harman [31]

Answer:

i mean its asking what your favorite sport is..

Explanation:

5 0
3 years ago
A particle initially located at the origin has an acceleration of a=3jm/s^2 and an initial velocity of Vi=5im/s.
-BARSIC- [3]

Given the particle's acceleration is

\vec a(t) = \left(3\dfrac{\rm m}{\mathrm s^2}\right)\vec\jmath

with initial velocity

\vec v(0) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath

and starting at the origin, so that

\vec r(0) = \vec 0

you can compute the velocity and position functions by applying the fundamental theorem of calculus:

\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u)\,\mathrm du

\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u)\,\mathrm du

We have

• velocity at time <em>t</em> :

\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \displaystyle \int_0^t \left(3\dfrac{\rm m}{\mathrm s^2}\right)\,\vec\jmath\,\mathrm du \\\\ \vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath \\\\ \boxed{\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath}

• position at time <em>t</em> :

\vec r(t) = \displaystyle \int_0^t \left(\left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)u\,\vec\jmath\right) \,\mathrm du \\\\ \boxed{\vec r(t) = \left(5\dfrac{\rm m}{\rm s}\right)t\,\vec\imath + \frac12 \left(3\frac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath}

8 0
3 years ago
What is a lunar eclipse 2 paragraph
konstantin123 [22]

A lunar eclipse occurs when the Moon passes directly behind Earth and into its shadow. This can occur only when the Sun, Earth, and the Moon are aligned (in syzygy) exactly or very closely so, with the planet in between. Hence, a lunar eclipse can occur only on the night of a full moon. The type and length of an eclipse depend on the Moon's proximity to either node of its orbit.

During a total lunar eclipse, Earth completely blocks direct sunlight from reaching the Moon. The only light reflected from the lunar surface has been refracted by Earth's atmosphere. This light appears reddish for the same reason that a sunset or sunrise does: the Rayleigh scattering of bluer light. Due to this reddish color, a totally eclipsed Moon is sometimes called a blood moon.

5 0
3 years ago
If the evaporator outlet temperature on an r410A system is 50f and the evaporator superheat is 10f, what is the evaporating pres
Olenka [21]

Answer:

So, the evaporating pressure of the R410A = 118 psig

Explanation:

Solution:

For R410A system:

Data Given:

Evaporator Outlet Temperature = 50°F

Evaporator Superheat = 10°F

Required:

Evaporating Pressure in the system = ?

For this, first of all, we need to calculate inlet temperature on R410A system from the given value of outlet temperature.

Evaporator inlet temperature is the difference of outlet temperature and evaporator superheat.

Evaporator inlet temperature = Outlet Temperature - Evaporator Superheat

Evaporator inlet Temperature = 50°F - 10°F

Evaporator inlet Temperature = 40°F

Now, as we have the inlet temperature and the R410A system. We can consult the pressure temperature chart or PT chart, which I have attached and highlighted the value of evaporating pressure for 40°F inlet temperature.

So, the evaporating pressure of the R410A = 118 psig

3 0
2 years ago
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