Answer:
The vapor-pressure lowering of the solution is 2,39 mmHg
Explanation:
The Raoult's law says that the vapor pressure of a solvent in a solution is always lower than the vapor pressure of the pure solvent. The vapor pressure lowering is directly proportional to the mole fraction of the solute. In mathematical terms that means:
ΔP = <em>(1)</em>
Where:
ΔP is the vapor-pressure lowering of the solution
is molar fraction of solute
And is the capor pressure of the pure solvent (86,0 mmHg)
The moles of naphthalene are:
<em>9,36x10⁻³ moles solute</em>
And the moles of benzene are:
0,328 moles solvent
Molar fraction of solute is:
<em>0,0278</em>
Replacing in (1)
<em>ΔP = 2,39 mm Hg</em>
I hope it helps!
Answer:
A) and D)
Explanation:
I just completed this assignment and these are the correct options!
This is most likely because of strong attractive forces between the water molecules and the solute particles.
Answer:
2.1 x 10⁻².
Explanation:
- Generally, the equilibrium constant (Keq) is the product of the concentration of the reaction products divided by the product of the concentration of the reaction reactants, each term is raised to a power equal to its coefficient in the balanced chemical reaction.
- For the given reaction: 2HF → H₂ + F₂,
Keq = [H₂][F₂] / [HF]²,
Keq = [H₂][F₂] / [HF]² = [8.4 x 10⁻³][8.4 x 10⁻³] / [5.82 x 10⁻²]² = 2.1 x 10⁻².