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Inessa05 [86]
3 years ago
13

Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients NH3(g) + O2(g) + CH4(g)

→ HCN (aq) + H2O(1)
Chemistry
1 answer:
alexira [117]3 years ago
5 0

Answer:

2NH_{3 (g)} + 3O_{2 (g)} +2CH_{4 (g)} --> 2HCN_{(aq)} + 6H_{2}O_{(l)}

Explanation:

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Titanium has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.58. If the radius of the Ti atom is 0.1445
Karolina [17]

The unit cell volume of the crystal is V_c = 9.9084*10^-^2^3 cm^3 / unit cell and the density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Data;

  • radius = 0.1445 nm
  • c/a = 1.58
  • A = 46.88 g/mol

<h3>Unit Cell Volume</h3>

The unit cell volume can be calculated as

V_c = 6R^2c\sqrt{3}\\

let's substitute the values into the formula

V_c = 6 * (1.445*10^-^8)^2 * 1.58 8 * a * \sqrt{3} \\a = 2R\\V_c = 6 * (1.445*10^-^8)^2 * 1.58* 2 * 1.445*10^-^8 * \sqrt{3}\\ V_c = 9.984*10^-^2^3 cm^3 / unit cell

The unit cell volume of the crystal is V_c = 9.9084*10^-^2^3 cm^3 / unit cell

<h3>Density of Ti</h3>

The density of titanium can be calculated as

\rho = \frac{nA}{V_c N_a}

  • n = 6 for hcp
  • A = 46.88 g/mol
  • Na = Avogadro's number

let's substitute the values into the formula

\rho = \frac{nA}{V_c Na}\\ \rho = \frac{6*46.88}{9.9084*10^-^2^3* 6.023*10^2^3} \\\rho = 4.71 g/cm^3

The density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Learn more on crystal lattice here;

brainly.com/question/6610542

8 0
2 years ago
Please help with Chemistry! Very urgent! I’ll give you 40 points
kvv77 [185]

Answer: 3. No displacement, zinc is most reactive.

4. Calcium Chloride, Calcium is most reactive.

5. No displacement, Copper is most reactive

6. No displacement, Calcium is most reactive

7. Hydrogen Oxide, Hydrogen is most reactive

8. Carbon oxide, Carbon is most reactive

9. No displacement, Aluminum is most reactive

10. Potassium Kryptide + Lead, no displacement, Potassium is most reactive.

5 0
3 years ago
How many molecules of ascorbic acid(vitaminC,<br> C6H8 O6 )are in a 500 mg<br> tablet?
Olegator [25]

Answer:

1.71 × 10²¹ molecules

Explanation:

1 gram is equal to 1000 milligrams. The mass in grams corresponding to 500 mg is:

500 mg × (1 g / 1000 mg) = 0.500 g

The molar mass of ascorbic acid is 176.12 g/mol. The moles corresponding to 0.500 grams of ascorbic acid are:

0.500 g × (1 mol/ 176.12 g) = 0.00284 mol

In 1 mole of ascorbic acid, there are 6.02 × 10²³ molecules of ascorbic acid (Avogadro's number). The molecules in 0.00284 moles are:

0.00284 mol × (6.02 × 10²³ molecules/ 1 mol) = 1.71 × 10²¹ molecule

7 0
3 years ago
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In the current model of the atom, ___. electrons and protons are mixed together in a solid sphere electrons orbit around the pos
kati45 [8]
Neutrons and protons are in the nucleus
electrons are on shells which orbit the nucleus
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3 years ago
Hey yall, join on kahoot: 1088134
Paraphin [41]

Answer:

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3 0
3 years ago
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