From right triangle trigonometry, we have the following:
![\displaystyle{ tan(35^o)= \frac{opposite \ side }{adjacent \ side }](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20tan%2835%5Eo%29%3D%20%5Cfrac%7Bopposite%20%5C%20side%20%7D%7Badjacent%20%5C%20side%20%7D%20)
,
where the "opposite side" means the opposite side to angle with measure
![35^o](https://tex.z-dn.net/?f=35%5Eo)
, and "adjacent side" means the adjacent side to angle with measure
![35^o](https://tex.z-dn.net/?f=35%5Eo)
.
![tan(35^o)](https://tex.z-dn.net/?f=tan%2835%5Eo%29)
is a constant which can be found using a calculator.
In the calculator of the pc press: view - scientific - 35 - tan.
This gives
![tan(35^o)=0.7](https://tex.z-dn.net/?f=tan%2835%5Eo%29%3D0.7)
Thus, back in the equation
![\displaystyle{ tan(35^o)= \frac{opposite \ side }{adjacent \ side }](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20tan%2835%5Eo%29%3D%20%5Cfrac%7Bopposite%20%5C%20side%20%7D%7Badjacent%20%5C%20side%20%7D%20)
we substitute as follows and solve:
![\displaystyle{0.7= \frac{x }{12 }\\\\](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B0.7%3D%20%5Cfrac%7Bx%20%7D%7B12%20%7D%5C%5C%5C%5C)
![x=0.7\cdot12=8.4](https://tex.z-dn.net/?f=x%3D0.7%5Ccdot12%3D8.4)
Answer: 8.4 cm
Answer:
My calculator said error and i tried looking it up it said error too. I'm sorry I tried, you'll have to do it by hand
Step-by-step explanation:
The third one would be the correct answer. I separately multiplied each number in the first section by each number in the second section. For instance, 0 x 2 is 0, 4 x 5 is 20, 5 x 3 is 15, and 2 x 0 is 0. All of these numbers are in the third answer.
if there are 2 rows then each row will have 78 members
Answer:
The value of
. The figure is also attached below.
Step-by-step explanation:
Considering the expression
![5x + 6(x - 2) - 8 (x - 3)](https://tex.z-dn.net/?f=5x%20%2B%206%28x%20-%202%29%20-%208%20%28x%20-%203%29)
If we have to find the vale of
, then
![5x + 6(x - 2) - 8 (x - 3)=0](https://tex.z-dn.net/?f=5x%20%2B%206%28x%20-%202%29%20-%208%20%28x%20-%203%29%3D0)
![5x+6x-12-8\left(x-3\right)=0](https://tex.z-dn.net/?f=5x%2B6x-12-8%5Cleft%28x-3%5Cright%29%3D0)
![5x+6x-12-8x+24=0](https://tex.z-dn.net/?f=5x%2B6x-12-8x%2B24%3D0)
![3x+12=0](https://tex.z-dn.net/?f=3x%2B12%3D0)
![\mathrm{Subtract\:}12\mathrm{\:from\:both\:sides}](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D12%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D)
![3x+12-12=0-12](https://tex.z-dn.net/?f=3x%2B12-12%3D0-12)
![3x=-12](https://tex.z-dn.net/?f=3x%3D-12)
![\mathrm{Divide\:both\:sides\:by\:}3](https://tex.z-dn.net/?f=%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D3)
![\frac{3x}{3}=\frac{-12}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%7D%7B3%7D%3D%5Cfrac%7B-12%7D%7B3%7D)
![x=-4](https://tex.z-dn.net/?f=x%3D-4)
Therefore, the value of
. The figure is also attached below.
Keywords: equation
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