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3 years ago

13

HELPPPPPPPPPPPPPPPPPPPPP

2 answers:

Vika [28.1K]3 years ago

5 0

Answer:

-1.9b + 7.8

Step-by-step explanation:

inn [45]3 years ago

4 0

Answer:

-1.9b + 7.8

Step-by-step explanation:

1.3b - 3.2b = -1.9b

Add that with 7.8 and you get -1.9b + 7.8

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The bottom of a 13-foot straight ladder is set into the ground 2.5 feet away from a wall. When the top of the ladder is leaned a

Sindrei [870]

Soulution :

16.47 HOPE THIS HELPS!!

6 0

3 years ago

Use the quadratic formula to solve the equation if necessary round to the nearest hundredth

densk [106]

-5y^2 + 2y + 2 = 0

y = -2 ± ✓4 - 4*-5*2. /. -10

y = -2 ± ✓44. / -10

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(-1+✓11)/-5. and (-1-✓11)/-5

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3 years ago

An amusement park recently increased the cost of a family season pass. The original price was $150. The new price is $183. What

viva [34]

Answer:

1.22%

Step-by-step explanation:

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6 0

3 years ago

Please answer both with work,please use a paper and picture, thanks

Irina-Kira [14]

Answer:

a. $\frac{\textbf{17}}{\textbf{4}}$

b. $\frac{\textbf{3}}{\textbf{8}}$

Step-by-step explanation:

a. $\textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}}$

A mixed fraction of the form $a\frac{x}{y} = a + \frac{x}{y}$

$\therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4}$

$= 4 + \frac{1}{4}$

$= \frac{\textbf{17}}{\textbf{4}}$

b. $\textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}}$

A mixed fraction of the form $-c\frac{a}{b} = - c - \frac{a}{b}$

$\therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8}$

$= 1 - \frac{5}{8}$

$= \frac{8 - 5}{8}$

$= \frac{\textbf{3}}{\textbf{8}}$

Hence, the answer.

8 0

3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

6 0

4 years ago