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Nataly [62]
3 years ago
13

HELPPPPPPPPPPPPPPPPPPPPP

Mathematics
2 answers:
Vika [28.1K]3 years ago
5 0

Answer:

-1.9b + 7.8

Step-by-step explanation:

inn [45]3 years ago
4 0

Answer:

-1.9b + 7.8

Step-by-step explanation:

1.3b - 3.2b = -1.9b

Add that with 7.8 and you get -1.9b + 7.8

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The 2-minute-and-43-second song “You’re Welcome” from the movie Moana has been used in more than 3,000 videos. What percent of t
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3 0
3 years ago
How many squares will be in the fifth figure
Phantasy [73]

Answer: 30

Step-by-step explanation:

see photo for work

5 0
3 years ago
The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,
Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

If the mean number of arrivals is 10

This means that \mu = 10

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is P(X \leq 10)

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045

P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045

P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023

P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076

P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189

P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378

P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631

P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901

P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126

P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251

P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831

58.31% probability that there are no more than 10 arrivals.

8 0
3 years ago
A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

V = s^2h = 5324

h = 5324 / s^2

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top s^2

Side area 4sh

Total surface area A = s^2 + 4sh

We can substitute h = 5324 / s^2

A = s^2 + 4s\frac{5324}{s^2}

A = s^2 + 21296/s

To find the minimum of this function, we can take the first derivative, and set it to 0

A' = 2s - 21296/s^2 = 0

2s = 21296/s^2

s^3 = 10648

s = \sqrt[3]{10648} = 22

h = 5324 / s^2 = 5324 / 22^2 = 11

4 0
3 years ago
A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo
Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

a)

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) 10X+5X+5X=300 => 20X = 300 => X = 15 days for the lessons

b) 5X+10X+8X = 300 => 23X = 300 => X = 13.04 days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) 10X+5X=300 => 15X = 300 => X = 20 days for the lessons

b) 5X+10X = 300 => 15X = 300 => X = 20 days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) 10(10/24)+5X+5X= 300 => X = 29.58 days for the lessons

b) 5(10/24)+10X+8X = 300 => X = 16.51 days for the tests

so at the end to complete both tasks they need 29.58 days

4 0
3 years ago
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