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2 years ago

Please help me I really don’t understand anything en this quiz

Mathematics

1 answer:

trasher [3.6K]2 years ago

8 0

Answer:

look at the point where s is the corner of the truangle, look at where the y and x intercepts

Step-by-step explanation:

S(-3, 2)

U(-1,1)

T(-2,4)

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NO LINKS NO FILES. After you add 3 to both sides of the equation 27 = m/6 - 3, what should you do next?

a_sh-v [17]

Answer:

Multiply each side by 6

Step-by-step explanation:

27 = m/6 - 3

Add 3 to each side

27+3 = m/6 - 3+3

30 = m/6

Multiply each side by 6

30*6 = m/6*6

180 = m

3 0

2 years ago

3² +4² = 5²,

AlekseyPX

Answer:

They are all true

Step-by-step explanation:

1. 3² +4² = 5²

3x3 + 4x4 = 5x5

9 + 16 = 25

25 = 25

-----------------------

2. 6² + 8² = 10²

36 + 64 = 100

100 = 100

------------------

3. 9² + 12² = 15²

81 + 144 = 225

225 = 225

-------------------

4. 5² +12² =13²

25 + 144 = 169

169 =169

-------------------

7 0

7 months ago

Please answer and no explanation needed

rewona [7]

Wait isn’t it 30 or am I reading it wrong?

3 0

2 years ago

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

3 years ago

Mitch completes the course and his boss promotes him. Mitch receives a 25% increase on his previous pay of $40 000 per year afte

kolezko [41]

Before her promotion, Mitch was receiving $40,000 per year after tax. Since the loan payment is 4%, therefore the money that goes to the loan is:

Loan payment = $40,000 * 0.04

Loan payment = $1,600

After her promotion, Mitch is now receiving:

New salary = $40,000 * 1.25

New salary = $50,000

Therefore the new loan payment becomes:

New loan payment = $50,000 * 0.04

New loan payment = $2,000

Therefore Mitch is paying an extra payment of:

$2,000 - $1,600 = $400

Answer: $400

4 0

2 years ago