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Murrr4er [49]
3 years ago
6

Please help me I really don’t understand anything en this quiz

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Answer:

look at the point where s is the corner of the truangle, look at where the y and x intercepts

Step-by-step explanation:

S(-3, 2)

U(-1,1)

T(-2,4)

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3 pe cat este egal cu 8 pe cat
NemiM [27]
Se puede escribir esto en Inglés por favor?
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3 years ago
Please help me, no links or random answers, please. When you are writing the answer please number it so I know which answer is f
meriva

Answer

A: (1,7.5)

b:(0,6)

c: because the graph is linear graph and have a constant rate of change/ slope which is -1.5

Step-by-step explanation:

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3 years ago
Solve the inequality and enter your solution as an inequality in the box below.
PSYCHO15rus [73]

Answer:

x > -10

Step-by-step explanation:

2 + x > -8

x > -8 - 2

x > -10

8 0
2 years ago
Read 2 more answers
Write an equation of the line with a slope of 2/3<br> and y -intercept of -8
Naddik [55]
Y = 2/3x + -8 or y = 2/3x - 8
4 0
3 years ago
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Marie is getting married tomorrow, at an outdoor ceremony in the desert. In recent years, it has rained only 5 days each year. U
kogti [31]

Answer:

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Forecast of rain.

Event B: Raining.

In recent years, it has rained only 5 days each year.

A year has 365 days. So

P(B) = \frac{5}{365} = 0.0137

When it actually rains, the weatherman correctly forecasts rain 90% of the time.

This means that P(A|B) = 0.9

Probability of forecast of rain:

90% of 0.0137(forecast and rains)

10% of 1 - 0.0137 = 0.9863(forecast, but does not rain)

P(A) = 0.0137*0.9 + 0.9863*0.1 = 0.11096

What is the probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

P(B|A) = \frac{0.0137*0.9}{0.11096} = 0.1111

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

3 0
3 years ago
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