The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
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Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²
Answer:
(8 x 9) x (2 x 5) is the correct answer.
Step-by-step explanation:
(8 x 9)= 72
(2 x 5)= 10
72 x 10 = 720
Answer:
Question 1: The hours that will pass between two consecutive times, when the water is at its maximum height is π hours
Question 2: Sin of the angle is -0.8
Step-by-step explanation:
Question 1: Here we have h(t) = 4·cos(t) + 10
The maximum water level can be found by differentiating h(t) and equating the result to zero as follows;
∴ sin(t) = 0
t = 0, π, 2π
Therefore, the hours that will pass between two consecutive times, when the water is at its maximum height = π hours.
Question 2:
B = (3, -4)
Equation of circle = x² + y² = 25
Here we have
Distance moved along x coordinate = 3
Distance moved along y coordinate = -4
Therefore, we have;
Sinθ = sin(-53.13) = -0.799≈ -0.8.
Rise over run so it would be 5 over -2.5 ?? I could be wrong:((
