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Lubov Fominskaja [6]
4 years ago
15

An object traveling at constant speed v in a circle of radius R has an acceleration am 5 m/s2. If both R and v are doubled, what

is the new
acceleration?
40 m/s2
10 m/s2
2.5 m/s?
5 m/s2
Physics
1 answer:
MakcuM [25]4 years ago
7 0

Answer:

im pretty sure its 10 m/s but its kinda hard sorry

Explanation:

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Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s
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Answer:

0.88 mm

Explanation:

Given

Wavelength of the atoms, λ = 502 nm = 502*10^-9 m

Radius of the screen away from the double slit, r = 1 m

We know that Y(20) = 11.4*10^-3 m

d = (20 * R * λ) / Y(20)

d = (20 * 1 * 502*10^-9)/11.4*10^-3

d = 1*10^-5 / 11.4*10^-3

d = 0.88 mm

Therefore, the distance of separation between the two slits is 0.88 mm

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Two satellites orbit the Earth in circular orbits of the same radius. One satellite is twice as massive as the other. Which stat
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To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.

This concept is expressed in the equation,

v = \sqrt{\frac{Gm_E}{r}}

Where,

G = Universal Gravitational constant

m_E = Mass of the Earth

Therefore the ratio of the velocity from two satellites is,

\frac{v_1}{v_2} = \sqrt{\frac{r_2}{r_1}}

The ratio between the two satellites is the same, then

\frac{v_1}{v_2} = \sqrt{\frac{r}{r}}

\frac{v_1}{v_2} = 1

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Squids are the fastest marine invertebrates, using a powerful set of muscles to take in and then eject water in a form of jet pr
tatuchka [14]

Answer:

0.25 m/s

Explanation:

This problem can be solved by using the law of conservation of momentum - the total momentum of the squid-water system must be conserved.

Initially, the squid and the water are at rest, so the total momentum is zero:

p_i = 0

After the squid ejects the water, the total momentum is

p_f = m_s v_s + m_w v_w

where

m_s = 1.60 kg is the mass of the squid

v_s is the velocity of the squid

m_2 = 0.115 kg is the mass of the water

v_w = 3.50 m/s is the velocity of the water

Due to the conservation of momentum,

p_i = p_f

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0=m_s v_s + m_w v_w

so we can find the final velocity of the squid:

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and the negative sign means the direction is opposite to that of the water.

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