Answer:
0.88 mm
Explanation:
Given
Wavelength of the atoms, λ = 502 nm = 502*10^-9 m
Radius of the screen away from the double slit, r = 1 m
We know that Y(20) = 11.4*10^-3 m
d = (20 * R * λ) / Y(20)
d = (20 * 1 * 502*10^-9)/11.4*10^-3
d = 1*10^-5 / 11.4*10^-3
d = 0.88 mm
Therefore, the distance of separation between the two slits is 0.88 mm
<span>vibrations that travel through the air or another medium and can be heard when they reach a person's or animal's ear.</span>
To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.
This concept is expressed in the equation,

Where,
G = Universal Gravitational constant
Mass of the Earth
Therefore the ratio of the velocity from two satellites is,

The ratio between the two satellites is the same, then



Therefore the correct option is B.
Answer:
0.25 m/s
Explanation:
This problem can be solved by using the law of conservation of momentum - the total momentum of the squid-water system must be conserved.
Initially, the squid and the water are at rest, so the total momentum is zero:

After the squid ejects the water, the total momentum is

where
is the mass of the squid
is the velocity of the squid
is the mass of the water
is the velocity of the water
Due to the conservation of momentum,

so

so we can find the final velocity of the squid:

and the negative sign means the direction is opposite to that of the water.