Answer:
a) E = 1.47 × 10^5 N/C
b) south
Explanation:
The magnitude of an electric field can be defined mathematically as;
E = F/q ........1
Where,
E = magnitude of the electric field
F = electric force
q = charge on the proton
Given;
F = 2.36 × 10^-14 N
Note that charge on a proton is known as Qp = 1.602 × 10^-19 C
q = 1.602 × 10^-19 C
Substituting into equation 1, we have;
E = 2.36 × 10^-14 N/1.602 × 10^-19 C
E = 1.47 × 10^5 N/C
b) The direction of the electric field;
From equation 1
E = F/q ........1
since both electric field and electric force are vector quantity and q is a positive charge (constant), then both the electric field and electric force would be parallel to each other. Therefore the electric field is directed to the south also.
(When a vector is multiplied by a positive constant the direction remains the same)
According to all the given requirements
stratosphere x starts at an altitude of 16 km
that means
<span>16≤x
</span> and,as given ,stratosphere ends at an altitude of 30 km:
which means
<span>x≤30</span>
combining both of them we get
<span>16≤x≤30</span>
So the range of the stratosphere is from 16 to 30 km.
Answer:
t = 2 s
Explanation:
As we know that fish is pulled upwards with uniform maximum acceleration
then we will have
here we know that maximum possible acceleration of so that string will not break is given as
now we have
now for such acceleration we can use kinematics
t = 2 s
D, I believe is the correct answer. Hope I answered your question, have a good day.<span />
