Answer:
йцу21241
Explanation:
ere taking their seats. Finn and Jan presented the progress they had made on the project since the last meeting. Everyone engaged in the subsequent discussions, asking questions and offering ideas.
Answer:
Por ela ter batido na trave, não tem como voltar 2x mais forte, por que toda ação correspondente a uma reação de igual intensidade, mas que atua no sentido oposto
Explanation:
Split the operation in two parts. Part A) constant acceleration 58.8m/s^2, Part B) free fall.
Part A)
Height reached, y = a*[t^2] / 2 = 58.8 m/s^2 * [7.00 s]^2 / 2 = 1440.6 m
Now you need the final speed to use it as initial speed of the next part.
Vf = Vo + at = 0 + 58.8m/s^2 * 7.00 s = 411.6 m/s
Part B) Free fall
Maximum height, y max ==> Vf = 0
Vf = Vo - gt ==> t = [Vo - Vf]/g = 411.6 m/s / 9.8 m/s^2 = 42 s
ymax = yo + Vo*t - g[t^2] / 2
ymax = 1440.6 m + 411.6m/s * 42 s - 9.8m/s^2 * [42s]^2 /2
ymax = 1440.6 m + 17287.2m - 8643.6m = 10084.2 m
Answer: ymax = 10084.2m
Answer:
These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation.
Explanation:
Answer:
164.87 J
Explanation:
From the question,
Work done (W) = mghcosθ........................ Equation 1
Where m = mass of the box, h = height, g = acceleration due to gravity, θ = angle to the vertical
Given: m = 25 kg, h = 2.6 meters, θ = 75°.
Constant: g = 9.8 m/s²
Substitute these value into equation 1
W = 25×9.8×2.6×cos75°
W = 164.87 J.
