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kenny6666 [7]
3 years ago
6

Order from least to greatest: The square root of 64, 8.8, 26/3, 8 2/7

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Square root 64 = 8

26/3 = 8 2/3 = 8.66666

8 2/7 = 8. 2857

So the order is sqrt(64) 8 2/7 26/3 8.8 <<<<< Answer

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(0.75*4) + (0.6*6) = 6.6

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the cost (in dollars) of making n birthday cakes is represented by C= 24n + 35. How many birthday cakes are made when the cost i
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n= 16

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A 47-foot-long piece of pipe is to be cut into three pieces. The second piece is three times as long as the first piece, and the
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A = first piece, b = second piece, c = third piece

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7 0
3 years ago
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
3 years ago
If you flip two coins at once, will at least one coin land on heads?
anzhelika [568]

Answer:

There is 3 out of 4 chance you will get one head.

You are not guaranteed to get a head

Step-by-step explanation:

Lets determine the sample space

HH  HT  TH  TT

These are the 4 things that can happen when we flip to coins

We want at least one head

3 of the 4 choices have at least 1 head

P (at least one head) = 3/4

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