In science how are solutions and mixtures alike, and how are they different? 28 points!!!!!!

Chemistry

1 answer:

ELEN [110]2 years ago

4 0

A solution is a mixture where one dissolves the other. the substance that dissolves is a solute

You might be interested in

An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 eV, 27 eV, and 48 eV. What

Fynjy0 [20]

Answer:

$l=3.5*10^{-10}m$

Explanation:

From the question we are told that:

1st Energy $E_1=12eV=4(3eV)$

2nd Energy $E_2=27eV=9(3eV)$

3rd Energy $E_3=48eV=16(3eV)$

Generally the equation for Energy E for electron in one dimensional box at ground state $E_0$ is mathematically given by

$E_0=\frac{h}{8ml^2}$

Therefore Length a is mathematically given as

$l=\sqrt{\frac{h^2}{8mE_0} }$

$l=\sqrt{\frac{(6.625*10^{-34})^2}{8(9.1*19^{-31}{(3eV(1.6*10^{-19}))}}$

$l=3.5*10^{-10}m$

8 0

2 years ago

You want to make 500 ml of a 1 N solution of sulfuric acid (H2SO4, MW: 98.1). How many grams of sulfuric acid do you need?

umka21 [38]

Answer:

24.525 g of sulfuric acid.

Explanation:

Hello,

Normality (units of eq/L) is defined as:

$N=\frac{eq_{solute}}{V_{solution}}$

Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:

$eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq$

Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:

$m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4$