What substance has the highest molar mass?

How many protons, electrons, and neutrons does an atom with atomic number

sergey [27]

Answer:

protons : 10

electron : 10

neutron : 10

Explanation:

Protons will usually be the same as the electrons when its a <u>Atom</u> (when its a ion or covalent bond or simple bond they will most likely be different)

the atomic number represents protons and electrons

the mass number - the atomic number = neutron

8 0

3 years ago

I need help with this anyone?

valkas [14]

Just look it up on goog^le or a chart

5 0

3 years ago

What are the sign and magnitude of the charge of atom containing 14 protons, 15 neutrons, and 12 electrons?

Karo-lina-s [1.5K]

<span>We know that protons gives positive charge, neutrons no charge and electrons negative, then +14 - 12 = +2 So the charge of the atom is sign positive and magnitude 2</span>

7 0

3 years ago

Many home barbeques are fueled with propane gas (C3H8)(C3H8). Part A What mass of carbon dioxide is produced upon the complete c

Andrew [12]

Answer:

41264 g of CO₂

Explanation:

Combustion reaction is:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

1 mol of propane react to 5 moles of oxygen in order to proudce 3 moles of carbon dioxide and 4 moles of water.

In a combustion reaction, our reactant reacts to oxygen and the products are always CO₂ and water.

We have the volume of propane but we need moles of it, so we need to apply density.

Density = mass / volume so mass = density . volume.

Density of propane is: 493 g/L

Mass of propane is 493 g/L . 27.9L = 13754.7 g

We convert mass to moles: 13754.7 g . 1 mol/ 44g = 312.6 moles

According to reaction, 1 mol of propane can produce 3 moles of CO₂

Our 312.6 moles will produce 312.6 . 3 = 937.8 moles

We convert moles to mass: 937.8 mol . 44 g/mol = 41264 g

3 0

3 years ago

Exactly 16 mL of a solution A is diluted to 300 mL, resulting in a new solution B that has 0.50 M concentration. If the solution

nordsb [41]

Answer:

8.77g

Explanation:

Step 1:

Data obtained from the question.

This includes the following:

Concentration of A (C1) =.?

Volume of A (V1) = 16 mL

Volume of B (V2) = 300 mL

Concentration of B (C2) = 0.50 M

Molar Mass of NaCl = 58.443 g/mol

Mass of NaCl =.?

Step 2:

Determination of the concentration of A.

Applying the dilution formula:

C1V1 = C2V2

The concentration of A i.e C1 can be obtained as follow:

C1V1 = C2V2

C1 x 16 = 0.5 x 300

Divide both side by 16

C1 = (0.5 x 300) / 16

C1 = 9.375 M

Therefore, the concentration of A is 9.375 M

Step 3:

Determination of the number of mole of NaCl in 9.375 M NaCl solution. This is illustrated below:

Molarity = 9.375 M

Volume = 16 mL = 16/1000 = 0.016 L

Mole of NaCl =?

Molarity = mole /Volume

Mole =Molarity x Volume

Mole of NaCl = 9.375 x 0.016

Mole of NaCl = 0.15 mole

Step 4:

Determination of the mass of NaCl. This is illustrated below:

Mole of NaCl = 0.15 mole

Molar Mass of NaCl = 58.443 g/mol

Mass of NaCl =?

Mass = number of mole x molar Mass

Mass of NaCl = 0.15 x 58.443

Mass of NaCl = 8.77g

Therefore, 8.77g of NaCl is needed to make 1 L of the original solution A.

7 0

3 years ago

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