Answer:
the answer is 10 times
Explanation:
because it takes 10 times as much energy -3330 j - to melt 10.0 grams of ice.
HCl is <span>limiting reactant, Mg in excess therefore:
</span><span>number of moles HCl:
75.0 mL in liters: 75.0 / 1000 => 0.075 L
Molarity HCl = 1.0 M
n = M x V
n = 1.0 x 0.075
n = 0.075 moles of HCl
</span>Mg(s) + 2 HCl (aq) = H2 (g) + MgCl2 (aq)
<span>2 moles HCl -------------------- 1 mole H2
</span><span>0.075 moles of HCl ------------ ( moles H2)
</span>
moles H2 = 0.075 x 1 / 2
moles H2 = 0.075 / 2
= 0.0375 moles of H2
hope this helps!
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Answer:
Reproduction may be asexual when one individual produces genetically identical offspring, or sexual when the genetic material from two individuals is combined to produce genetically diverse offspring.
Answer: i believe it’s the second one !
Answer:
ΔH = -20kJ
Explanation:
The enthalpy of formation of a compound is defined as the change of enthalpy during the formation of 1 mole of the substance from its constituent elements. For H₂S(g) the reaction that describes this process is:
H₂(g) + S(g) → H₂S(g)
Using Hess's law, it is possible to sum the enthalpies of several reactions to obtain the change in enthalpy of a particular reaction thus:
<em>(1) </em>H₂S(g) + ³/₂O₂(g) → SO₂(g) + H₂O(g) ΔH = -519 kJ
<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ
<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ
The sum of -(1) + (2) + (3) gives:
<em>-(1) </em>SO₂(g) + H₂O(g) → H₂S(g) + ³/₂O₂(g) ΔH = +519 kJ
<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ
<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ
<em>-(1) + (2) + (3): </em><em>H₂(g) + S(g) → H₂S(g) </em>
<em>ΔH =</em> +519kJ - 242kJ - 297kJ = <em>-20 kJ</em>
<em />
I hope it helps!
