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melomori [17]
3 years ago
7

When a carbon atom joints chemically with an oxygen atom it makes carbon monoxide what is the term for carbon monoxide?

Chemistry
1 answer:
olganol [36]3 years ago
5 0

Answer:

A

Explanation:

I learned this last year

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When you calculate results that are aiming for known values, the percent error formula is useful tool for determining the precision of your calculations. The formula is given by: The experimental value is your calculated value, and the theoretical value is your known value.
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Why is it important that humans (and other animals) maintain a relatively constant body temperature?
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flammability is a material's ability to burn in the presence of a. hydrogen b. nitrogen c. oxygen d. carbon dioxide
Olegator [25]

Oxygen.

<h3>Further explanation</h3>

Chemical properties can be observed only when the substance changes into one or more different substances through chemical reactions or transformations. One of the chemical properties is flammability.

Flammability is a material's ability to burn in the presence of oxygen.

Remember, oxygen doesn't burn. Precisely flammable substances obtain substances that burn. Oxygen remains an oxidizing agent, which means it supports the combustion process. Oxygen causes other objects to catch fire at low temperatures and burns hotter and faster. But oxygen itself does not burn. Consequently, if you at present deliver fuel and fire, adding oxygen will provide the fire.

Carbon dioxide is the result of combustion. An example can be seen in firewood in a fireplace. One of the chemical properties of carbon-based wood is having the ability to burn. Chemically the wood turns into carbon dioxide when it burns and leaves a residue of ash. Furthermore, this ash residue cannot be turned back into the wood. Chemical changes result in new substances.

Consider an example of a combustion reaction to methane gas:

\boxed{ \ CH_4_{(g)} + 2O_2_{(g)} \rightarrow CO_2_{(g)} + 2H_2O_{(g)} \ }

Our balanced equation for methane combustion implies that every one CH₄ molecule reacts with two O₂ molecules. The product of combustion is one carbon dioxide molecule and two steam or water vapor molecules.

<h3>Learn more</h3>
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Keywords: flammability, a material's ability to burn in the presence of oxygen, hydrogen, nitrogen, carbon dioxide, chemical properties, reactions,  the combustion process, oxidizing agent, the result

4 0
3 years ago
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What is the percent ionization of a monoprotic weak acid solution that is 0.188 M? The acid-dissociation (or ionization) constan
djyliett [7]

Answer: The percent ionization of a monoprotic weak acid solution that is 0.188 M is 3.59\times 10^{-4}\%

Explanation:

Dissociation of weak acid is represented as:

HA\rightleftharpoons H^+A^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.188 M and \alpha = ?

K_a=2.43\times 10^{-12}

Putting in the values we get:

2.43\times 10^{-12}=\frac{(0.188\times \alpha)^2}{(0.188-0.188\times \alpha)}

(\alpha)=3.59\times 10^{-6}=3.59\times 10^{-4}\%

Thus percent ionization of a monoprotic weak acid solution that is 0.188 M is 3.59\times 10^{-4}\%

5 0
3 years ago
In 3 moles of ethane calculate the following.
Arte-miy333 [17]
The chemical formula of ethane is C2H6 which means that every mole of ethane contains 2 moles of carbon atom and 6 moles of hydrogen atom.
 
a. (3 moles) x (2 moles C atom / 1 mole ethane) = 6 moles C atom
b. (3 moles) x (6 moles H atom / 1 mole ethane) = 18 moles H atom
c. (3 moles ethane) x (6.022 x 10^23 molecules / 1 mole) = 1.8 x 10^24 molecules. 
6 0
3 years ago
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