When you calculate results that are aiming for known values, the percent error formula is useful tool for determining the precision of your calculations. The formula is given by: The experimental value is your calculated value, and the theoretical value is your known value.
Oxygen.
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Further explanation</h3>
Chemical properties can be observed only when the substance changes into one or more different substances through chemical reactions or transformations. One of the chemical properties is flammability.
Flammability is a material's ability to burn in the presence of oxygen.
Remember, oxygen doesn't burn. Precisely flammable substances obtain substances that burn. Oxygen remains an oxidizing agent, which means it supports the combustion process. Oxygen causes other objects to catch fire at low temperatures and burns hotter and faster. But oxygen itself does not burn. Consequently, if you at present deliver fuel and fire, adding oxygen will provide the fire.
Carbon dioxide is the result of combustion. An example can be seen in firewood in a fireplace. One of the chemical properties of carbon-based wood is having the ability to burn. Chemically the wood turns into carbon dioxide when it burns and leaves a residue of ash. Furthermore, this ash residue cannot be turned back into the wood. Chemical changes result in new substances.
Consider an example of a combustion reaction to methane gas:

Our balanced equation for methane combustion implies that every one CH₄ molecule reacts with two O₂ molecules. The product of combustion is one carbon dioxide molecule and two steam or water vapor molecules.
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Keywords: flammability, a material's ability to burn in the presence of oxygen, hydrogen, nitrogen, carbon dioxide, chemical properties, reactions, the combustion process, oxidizing agent, the result
Answer: The percent ionization of a monoprotic weak acid solution that is 0.188 M is
Explanation:
Dissociation of weak acid is represented as:
cM 0 0
So dissociation constant will be:
Give c= 0.188 M and
= ?
Putting in the values we get:
Thus percent ionization of a monoprotic weak acid solution that is 0.188 M is
The chemical formula of ethane is C2H6 which means that every mole of ethane contains 2 moles of carbon atom and 6 moles of hydrogen atom.
a. (3 moles) x (2 moles C atom / 1 mole ethane) = 6 moles C atom
b. (3 moles) x (6 moles H atom / 1 mole ethane) = 18 moles H atom
c. (3 moles ethane) x (6.022 x 10^23 molecules / 1 mole) = 1.8 x 10^24 molecules.