The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2
The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2
Hope this helps:) plz mark brainiest i would really apperciate it
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For the following relation the domain would be all of the x coordinates.
D=A. 2,0,4,5
Answer:
Graph
Step-by-step explanation:
The graph swapped the y and x axis values.
The answer should be f(x)=9x + 60
Answer:
Option C) The first equation is y= 2/3x-4 when written in slope-intercept form .
Step-by-step explanation:
We have
The first equation is in Standard form .
Convert to slope Intercept form .
Isolate the Variable y .
Divide by 3 both sides .
The second equation is in slope Intercept form .
Convert to standard form
Multiply by 5 both sides to remove the fraction .
<h3><u>Verify each statement :- </u></h3>
<h3>• case A) Both equations are in slope-intercept form.</h3>
- Because only the second equation is in slope -intercept form
<h3>• case B) Neither equation is in slope-intercept form .</h3>
- Because, the second equation is in slope -intercept form
<h3>• case C) The first equation is y= 2/3x-4 when written in slope-intercept form</h3>
<h3>• case D)The second equation is 3x+5y=10 when written in slope-intercept form.</h3>
- Because, the second equation is 3x+5y=10 when written in standard form .
<h2>I hope this helps you !! </h2>
