Answer:
Step-by-step explanation:
the answer is D. 6 ≤ x < ∞
Answer:
(2,16)
Step-by-step explanation:
y=8x-----------(i)
y= 10x-4---------(ii)
Substituting the value of y=8x in equation (ii)
8x=10x-4
8x-10x=-4
-2x= -4
x=2
Now, substituting the value of x= 2 in equation (i)
y=8x=8(2)=16
Solution of the system is (2,16)
Answer:
To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
Step-by-step explanation:
(Khan Academy)
We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
