X cubed (³) + x
x³ + x Plug in 2 for x
2³ + 2 Cube 2 (2 x 2 x 2)
8 + 2 Add
10
P(3) = 1/6
Number of attempt = 400
P(3) = 1/6 x 400 = 66.67 times.
Therefore the frequency can be between (B) 64 to (C) 70 times.
Answer (B) 64 and (C) 70
The answer to the question is it would add twenty seven every two times it goes up
The legnth is irrelivant
we know that
Circumference=2 times pi time radius
c=40
40=2 times pi times radius
divide both sides by 2
20=pi times radius
divide both sides b pi
20/pi=radius
the radius is 20/pi cm or aproximately 6.366199048 cm