Answer:
Free body diagram
Explanation:
A free body diagram shows all the forces acting on an object. an example would be a box sitting on the floor.
Draw a square and you would have an arrow from the box pointed down to represent gravity pulling the box down and an arrow from the box pointing upwards to represent the normal force of the ground pushing back. in the scenario the two arrows would be equal length because the forces balance out since the box is motionless. in a situation where there is motion one arrow would be bigger such as if a box was falling. in this example it would have an arrow down to show gravity but no arrow up because it is in free fall. The sum of the forces which is represented by the arrows is what your net force is. The free body diagram helps you visualize all the forces acting on an object.
Look at periodic table and see that it is metal .
The flux through a surface is given by the scalar product of the field strength and the area
of the surface.
As the rectangular surface is in xy plane the flux corresponding to x and y component of
field will be zero (parallel to the surface) and the flux through the surface is only due to z
component of the field.
Because flux is the dot product of Electric field and area vector. So, parallel to surface is 0.
So,
The z component of the field is varying with x only and directly
proportional to x coordinate. (cx k)
Consider an infinitely thin strip of the surface at a distance x from y axis of thickness dx as
in figure. Field at this strip will have magnitude c*x and will be normal to the surface hence
the flux through this strip will be given by :
Answer:
The answer to the questions is;
In terms of standing waves, the listener moves from a location with high amplitude to one with lower amplitude or vibration (anti-node to node)
The distance 4.1 cm is equivalent to λ/4
Explanation:
For standing waves we have is a stationary wave comprising of two opposite direction moving waves that have equal amplitude and frequency, resulting in the superimposition of the waves. As such certain points are fixed along the wave path that is the peaks amplitude of the wave oscillation is constant at a particular point. A node occurring at a point and an anti-node occurring at another fixed point
When the listener moves 4.1 cm he or she has left the anti-node to the node hence the faintness of the sound
The distance from the node to the anti-node is 1/4 wavelength, or 1/4×λ
Therefore 4.1 cm is λ/4