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USPshnik [31]
3 years ago
7

An experiment measures the growth of crystals in a liquid solution aboard the space shuttle. A collection of bottles has the liq

uid in varying strength, or concentration of the tested substance. What would be a control observation in this experiment?
A. the bottle with 0% concentration
B. the bottle with the weakest concentration
C. the bottle with the strongest concentration
D. the bottle with the medium amount of concentration
Physics
2 answers:
Fantom [35]3 years ago
7 0

the control would be A. the bottle with 0% concentration, because you're not changing anything.

gayaneshka [121]3 years ago
7 0

Answer:

A. the bottle with 0% concentration

Explanation:

In teh bottle with the 0% concentration you can create a control observation of the experiement to see how it beheaves even if it has no concentration and if it really depend on the substance added or is something that happens naturally in those environments.  Remember that when doing experiments you should always have a sample of the subject that is given nothing in order to observe the normal behaviour of the subject under no studies.

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A magnet can attract or repel another magnet from a distance true or false?
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Read 2 more answers
A stone is dropped from the upper observation deck of a tower, "500" m above the ground. (Assume g = 9.8 m/s2.) (a) Find the dis
Yuri [45]

Answer:

h₍₁₎ = 495,1 meters

h₍₂₎ = 480,4 m

h₍₃₎ = 455,9 m

...

..

Explanation:

The exercise is "free fall". t = \sqrt{\frac{2h}{g} }

Solving with this formula you find the time it takes for the stone to reach the ground (T) = 102,04 s

The heights (h) according to his time (t) are found according to the formula:

h(t) = 500 - 1/2 * g * t²

Remplacing "t" with the desired time.

4 0
3 years ago
A.
Brut [27]

Answer:

\boxed{\sf Work \ done = 4 \ J}

Given:

Force = 8 N

Distance covered by the body = 50 cm = 0.5 m

Explanation:

Work Done = Force × Distance covered by the body

= 8 × 0.5

= 4 J

6 0
2 years ago
physics A river flows at a speed vr = 5.37 km/hr with respect to the shoreline. A boat needs to go perpendicular to the shorelin
vova2212 [387]

Answer: Vb is the vector  (-5.37m/s,  8.59 m/s), with a module 10.13m/s

then the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9

Explanation:

We can use the notation (x, y) where the river flows in the x-axis and the pier is on the y-axis.

We have Vr = (5.37m/s, 0m/s)

Now, if the boat wants to move only along the y-axis (perpendicularly to the shore).

The velocity of the boat Vb will be:

Vb = (-c*sin(32). c*cos(32))

Then we should have that:

5.37 m/s - c*sin(32) = 0

c = (5.37/sin(32))m/s = 10.13 m/s

the velocity in the y-axis is:

10.13m/s*cos(32) = 8.59 m/s

So Vb = (-5.37m/s,  8.59 m/s)

the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9 where i used Vb as the module of the boat's velocity.

7 0
2 years ago
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