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USPshnik [31]
3 years ago
7

An experiment measures the growth of crystals in a liquid solution aboard the space shuttle. A collection of bottles has the liq

uid in varying strength, or concentration of the tested substance. What would be a control observation in this experiment?
A. the bottle with 0% concentration
B. the bottle with the weakest concentration
C. the bottle with the strongest concentration
D. the bottle with the medium amount of concentration
Physics
2 answers:
Fantom [35]3 years ago
7 0

the control would be A. the bottle with 0% concentration, because you're not changing anything.

gayaneshka [121]3 years ago
7 0

Answer:

A. the bottle with 0% concentration

Explanation:

In teh bottle with the 0% concentration you can create a control observation of the experiement to see how it beheaves even if it has no concentration and if it really depend on the substance added or is something that happens naturally in those environments.  Remember that when doing experiments you should always have a sample of the subject that is given nothing in order to observe the normal behaviour of the subject under no studies.

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Explanation:

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A) Determine the x and y-components of the ball's velocity at t = 0.0s, 2.0, 3.0 secs.
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The kinematic relationships we can find the position, acceleration and launch angle of the body on the planet Exidor.

a) the position are

      time (s)  x (m)   y(m)

        0            0          0

        2.0         3.6        1.2

        3.0         5.4        0.9

b) The aceleration is  g = 0.6 m / s²

c) The launch angle      θ = 33.7º

given parameters

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  • the movement times t = 1.0s, 2.0s and 3.0 s

to find

    a) position

    b) acceleration

    c) launch angle

Projectile launch is an application of kinematics to the movement of the body in two dimensions where there is no acceleration on the x axis and the y axis has the planet's gravity acceleration

b) To calculate the acceleration of the plant acting on the y-axis, we use that the vertical velocity of the body at the highest point is zero.

         v_y = v_{oy} - g t

where v and v({oy}  are the velocities of the body, g the acceleration of the planet's gravity and t the time

          0 = v_{oy} - gt

           g = v_{oy} / t

from the graph we observe that the highest point occurs for t = 2.0 s

           g = 1.2 / 2.0

           g = 0.6 m / s²

 

a) The position is requested for several times

X axis

in this axis there is no acceleration so we can use the uniform motion relationships

          vₓ = x / t

          x = vₓ t

where x is the position, vx is the velocity and t is the time

we calculate for the time

t = 0.0 s

          x₀ = 0

           

t = 2.0 s

          x₂ = 1.8 2

          x₂ = 3.6 m

t = 3.0 s

          x₃ = 1.8 3

          x₃ = 5.4 m

Y axis

In this axis there is the acceleration of the planet, let us use for the position the relation

          y = v_{oy} t - ½ g t²

t = 0.0 s

          y₀ = 0

          y₀ = 0 m

t = 2.0 s

         y₂ = 1.2 2 - ½ 0.6 2²

         y₂ = 1.2 m

t = 3.0 s

        y₃ = 1.2  3 - ½  0.6  3²

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measured counterclockwise from the positive side of the x-axis

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      time (s)  x (m)   y(m)

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        3.0         5.4        0.9

b) The aceleration is  g = 0.6 m / s²

c) The launch angle      θ = 33.7ºto)

learn more about projectile launch here:

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Answer:

Explanation:

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So, Time period, T = 1 s

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Answer:

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LAW 2: For a given metal, there exists a certain frequency below which the photoelectric emission does not take place. This frequency is called threshold frequency.

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LAW 3: For a frequency greater than the threshold frequency, the kinetic energy of photoelectrons is dependent upon frequency or wavelength but not on the intensity of light.

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Explanation:

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