Continent
jig-saw shapes when puzzled and combined together, formed one big continent -
Pangea, and was separated by drifts.
Fossil
comparisons of different species were discovered into two different, separated
continents in which when you combine them, they were one in the past.
Seismic,
volcanic, and geothermal activity are found along imagined plate
boundaries.
Plates
were actually rubbing against each other as evidence is seen on the formed
mountain ranges.
<span>
Paleomagnetism,
magnetic field placement in the layers of the rock are present.</span>
<h2>Answer: electrostatic and gravitational force
</h2><h2 />
Mechanical energy remains constant (conserved) if only <u>conservative forces</u> act on the particles.
In this sense, the following forces are conservative:
-Gravitational
-Elastic
-Electrostatics
While the Friction Force and the Magnetic Force are not conservative.
According to this, mechanical energy is conserved in the presence of electrostatic and gravitational forces.
Answer:
Electric field acting on the electron is 127500 N/C.
Explanation:
It is given that,
Mass of an electron, ![m=9.11\times 10^{-31}\ kg](https://tex.z-dn.net/?f=m%3D9.11%5Ctimes%2010%5E%7B-31%7D%5C%20kg)
Charge on electron, ![q=1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
Initial speed of electron, u = 0
Final speed of electron, ![v=3\times 10^7\ m/s](https://tex.z-dn.net/?f=v%3D3%5Ctimes%2010%5E7%5C%20m%2Fs)
Distance covered, s = 2 cm = 0.02 m
We need to find the electric field required. Firstly, we will find the acceleration of the electron from third equation of motion as :
![a=\dfrac{v^2-u^2}{2s}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2s%7D)
![a=\dfrac{(3\times 10^7)^2-0}{2\times 0.02}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B%283%5Ctimes%2010%5E7%29%5E2-0%7D%7B2%5Ctimes%200.02%7D)
![a=2.25\times 10^{16}\ m/s^2](https://tex.z-dn.net/?f=a%3D2.25%5Ctimes%2010%5E%7B16%7D%5C%20m%2Fs%5E2)
According to Newton's law, force acting on the electron is given by :
F = ma
![F=9.1\times 10^{-31}\times 2.25\times 10^{16}](https://tex.z-dn.net/?f=F%3D9.1%5Ctimes%2010%5E%7B-31%7D%5Ctimes%202.25%5Ctimes%2010%5E%7B16%7D)
![F=2.04\times 10^{-14}\ N](https://tex.z-dn.net/?f=F%3D2.04%5Ctimes%2010%5E%7B-14%7D%5C%20N)
Electric force is given by :
F = q E, E = electric field
![E=\dfrac{F}{q}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BF%7D%7Bq%7D)
![E=\dfrac{2.04\times 10^{-14}}{1.6\times 10^{-19}}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B2.04%5Ctimes%2010%5E%7B-14%7D%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%7D)
E = 127500 N/C
So, the electric field is 127500 N/C. Hence, this is the required solution.
Answer:a substance with low ability or no ability to conduct energy
Explanation: