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3 years ago

Three-quarters of the elements are..

Chemistry

1 answer:

Dennis_Churaev [7]3 years ago

8 0

Answer:

metals

Explanation:

Approximately three-quarters of all known chemical elements are metals. The most abundant varieties in the Earth's crust are aluminum,... Gold (Au), chemical element, a dense lustrous yellow precious metal of Group 11 (Ib), Period 6, of the periodic table.

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How many kJ are 3,340J?

forsale [732]

The answer I believe is 3.340kj.

8 0

3 years ago

the temperature of a sample of water increases from 20celsius to 46.6celsius as it absorbs 5650 J of heat. what is the mass of t

Levart [38]

Answer:

m = 50.74 kg

Explanation:

We have,

Initial temperature of water is 20 degrees Celsius

Final temperature of water is 46.6 degrees Celsius

Heat absorbed is 5650 J

It is required to find the mass of the sample. The heat absorbed is given by the formula ad follows :

$Q=mc\Delta T$

c is specific heat of water, c = 4.186 J/g°C

So,

$m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{5650}{4.186\times (46.6-20)}\\\\m=50.74\ kg$

So, the mass of the sample is 50.74 kg.

8 0

3 years ago

In order for a solute to dissolve in a solvent, what must be true?

Alex Ar [27]

The solute has to be hydrophilic, (water loving).

6 0

3 years ago

How much energy is needed to completely boil a 5.05g sample of water?

Keith_Richards [23]

Given what we know, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

<h3>Why does it take this much energy to boil the water?</h3>

We arrive at this number by taking into account the energy needed to boil 1g of water to its vaporization point. This results in the use of 2260 J of heat energy. We then take this number and multiply it by the total grams of water being heated, in this case, 5.05g, which gives us our answer of 11.4 kJ of energy required.

Therefore, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

To learn more about the behavior of water visit:

brainly.com/question/1416592?referrer=searchResults

8 0

2 years ago

A chemist has a 2.0 M solution of copper (II) sulfate. Is he takes 400 mL of this solution and dilutes it with 1200 mL of water,

Ksenya-84 [330]

0.66 M is the accurate molarity of the new solution of volume of 1200 ml.

Explanation:

Data given:

molarity of copper(II) sulphate, Mconc.= 2M

volume of 2M solution taken Vconc. = 400 ml

volume taken for dilution, Vdilute = 1200 ml

molarity of the diluted solution, Mdilute =?

We will use the formula for dilution as

Mconc Vconc = Mdilute x V dilute (conc is concentrated)

putting the values in the equation:

2 x 400 = Mdilute x 1200

Mdilute = $\frac{800}{1200}$

Mdilute = 0.66 M

When the solution is diluted to the volume of 1200 ml its molarity changes to 0.66 M.

4 0

3 years ago