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AlladinOne [14]
3 years ago
5

Pressure __________ with depth to support the fluid weight above.

Physics
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

B. Increases, also B is before C

Explanation:

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What is a hypothesis?
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A

Explanation:

a statement that can be tested through the scientific method

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Name at least three physical properties of the bowling ball.
HACTEHA [7]

The bowling ball is round in shape and red in color.

The bowling ball is smooth and hard.


*The shape of the bowling ball is round.

The color of the bowling ball is red.

The bowling ball is hard.

The bowling ball is smooth.

5 0
3 years ago
Read 2 more answers
WhAt is this question??????????
valina [46]

Answer:

Period = 7

Group = Actinides group

Family = Actinides Family

Explanation:

uranium found in seventh row or seventh period of the periodic table.

uranium is the member of Actinoides group it is also called Actinide group, And it has element whose atomic is number is 89 to 103. The atomic number of the uranium is 92. So, the uranium element is belongs to Actinide group

Uranium found in actinide family of periodic table, and actinides family has element whose atomic number is greater than or equal to 89 and less than or equal to 103.

8 0
3 years ago
A rotating wheel requires 5 s to rotate 38 revolutions. Its angular velocity at end of time interval 5-s is 79 rad/s. What is th
Lera25 [3.4K]

"Rotating wheel" is meant to indcate that the wheel is already rotating at the start. Denote the initial angular velocity by <em>ω₀</em>. Then the angular displacement <em>θ</em> at time <em>t</em> is

<em>θ</em> = <em>ω₀t</em> + 1/2 <em>αt</em> ²

while the angular velocity <em>ω</em> is

<em>ω</em> = <em>ω₀</em> + <em>αt</em>

<em />

It takes 5 s for the wheel to rotate 38 times, or turn a total of (2<em>π</em> rad/rev) (38 rev) = 76<em>π</em> rad, as well as to reach an angular velocity of 79 rad/s, so that

76<em>π</em> rad = <em>ω₀</em> (5 s) + 1/2 <em>α</em> (5 s)²

79 rad/s = <em>ω₀</em> + <em>α</em> (5 s)

Solve the second equation for <em>ω₀</em> and substitute into the first equation, then solve for <em>α</em> :

<em>ω₀</em> = 79 rad/s - <em>α</em> (5 s)

==>   76<em>π</em> rad = (79 rad/s - <em>α</em> (5 s)) (5 s) + 1/2 <em>α</em> (5 s)²

==>   76<em>π</em> rad = (79 rad/s) (5 s) - 1/2 <em>α</em> (5 s)²

==>   1/2 <em>α</em> (5 s)² = (79 rad/s) (5 s) - 76<em>π</em> rad

==>   <em>α</em> = ((79 rad/s) (5 s) - 76<em>π</em> rad) / (1/2 (5 s)²)

==>   <em>α</em> ≈ 12.5 rad/s²

3 0
3 years ago
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