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Dennis_Churaev [7]
3 years ago
15

Humans can typically perceive frequencies that range from 20 Hz–20 kHz. Dogs can hear sounds up to 45 kHz. Dog whistles produce

sound waves that range from 23–54 kHz; therefore, they cannot be heard by the human ear.
Which statement accurately describes the pitch and wavelength of the sound waves produced by a dog whistle?

high pitch with a long wavelength
high pitch with a short wavelength
low pitch with a short wavelength
low pitch with a long wavelength
Physics
2 answers:
Aleksandr [31]3 years ago
6 0
Pitch is directly related to the frequency of the sound. In this item, we are given that the frequency of the sound is higher compared to those which are audible to the human being's ears. The pitch therefore of the dog's whistle is high. 

On the other hand, the frequency and the wavelength of a certain wave are inversely proportional. This means that the high frequency wave will have a short wavelength. 

Hence, the answer to this item would have to be "high pitch with a short wavelength" 

The answer to this item is the second option. 
Svetach [21]3 years ago
6 0
High pitch with a short wavelength 

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Four copper wires of equal length are connected in series. Their cross-sectional areas are 1.6 cm2 , 1.2 cm2 , 4.4 cm2 , and 7 c
EleoNora [17]

Answer:

63.8 V

Explanation:

We are given that

A_1=1.6 cm^2=1.6\times 10^{-4} m^2

1 cm^2=10^{-4} m^2

A_2=1.2 cm^2=1.2\times 10^{-4} m^2

A_3=4.4 cm^2=4.4\times 10^{-4} m^2

A_4=7 cm^2=7\times 10^{-4} m^2

Potential difference,V=140 V

We know that

R=\frac{\rho l}{A}

According to question

l_1=l_2=l_3=l_4=l

In series

R=R_1+R_2+R_3+R_4

R=\rho l(\frac{1}{A_1}+\frac{1}{A_2}+\frac{1}{A_3}+\frac{1}{A_4})

R=\rho l(\frac{1}{1.6\times 10^{-4}}+\frac{1}{1.2\times 10^{-4}}+\frac{1}{4.4\times 10^{-4}}+\frac{1}{7\times 10^{-4}})

R=\rho l(18284.6)

I=\frac{V}{R}=\frac{140}{\rho l\times 18284.6}

Potential across 1.2 square cm=V_1=IR_1=\frac{140}{\rho l\times 18284.6}\times \rho l(\frac{1}{1.2\times 10^{-4}}=63.8 V

Hence, the voltage across the 1.2 square cm wire=63.8 V

3 0
3 years ago
Oil explorers set off explosives to make loud sounds, then listen for the echoes from underground oil deposits. Geologists suspe
Elenna [48]

Answer:

dg= 942m

Explanation:

given the depth of the granite Us dg = 500m

time between the explosion t = 0.99s

the speed of sound in granite is Vg = 6000m/s

First of all calculate the time it takes the sound waves to travel down through the lake

Vw = dw/t1

t1 = dw/Vw

t1 = 500/1480

t1 = 0.338s.

Let dg be the depth of the granite basin, so the time it takes for the sound to travel down through the granite is t2 = dg/6000m/s......equation(1)

So the total time it takes to travel down to the oil surface will be

t1/2 = t1 + t2

t1/2=  0.338 + dg/6000.

since the reflection on the oil does not change the speed of sound, the sound will take travelling upto the surface the same time it takes to reach the oil

so; t = 2 t1/2

t1/2 = t/2 = 0.99s/2 = 0.495

Now insert into the values of t1/2 into the equation (1) and solve for dg;

we get 0.495 = 0.338 + dg/6000

dg = (0.495 - 0.338) x 6000

dg = 942m.

3 0
3 years ago
Read 2 more answers
An electric motor in a hair dryer is running at its normal constant operating speed and, thus, is drawing a relatively small cur
svlad2 [7]

Answer:

The temperature of the coil will increase (over heating will occur)

Explanation:

This overheating generally occurs when the motor is overloaded, when a bearing seizes up, when something locks the motor shaft and prevents it from turning, or when the motor simply fails to start properly.

Back emf is zero when the motor is not turning, and it increases proportionally to the motor's angular velocity. As the motor turns faster and faster, the back emf grows, always opposing the driving emf, and reduces the voltage across the coil and the amount of current it draws.

3 0
3 years ago
The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of 1.67
Lady bird [3.3K]

Explanation:

The nucleus of an atom can be modeled as several protons and neutrons closely packed together.

Mass of the particle, m=1.67\times 10^{-27}\ kg

Radius of the particle, R=10^{-15}\ m

(a) The density of the nucleus of an atom is given by mass per unit area of the particle. Mathematically, it is given by :

d=\dfrac{m}{V}, V is the volume of the particle

d=\dfrac{m}{(4/3)\pi r^3}

d=\dfrac{1.67\times 10^{-27}}{(4/3)\pi (10^{-15})^3}

d=3.98\times 10^{17}\ kg/m^3

So, the density of the nucleus of an atom is 3.98\times 10^{17}\ kg/m^3.

(b) Density of iron, d'=7874\ kg/m^3

Taking ratio of the density of nucleus of an atom and the density of iron as :

\dfrac{d}{d'}=\dfrac{3.98\times 10^{17}}{7874}

\dfrac{d}{d'}=5.05\times 10^{13}

d=5.05\times 10^{13}\ d'

So, the density of the nucleus of an atom is 5.05\times 10^{13} times greater than the density of iron. Hence, this is the required solution.

7 0
4 years ago
a lorry travels 3600m on a test track accelerating constantly at 3m/s squared from standstill. what is the final velocity (3 sig
suter [353]

The final velocity of the truck is found as 146.969 m/s.

Explanation:

As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.

Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}

Then, the final velocity will be

v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s

Thus,  the final velocity of the truck is found as 146.969 m/s.

8 0
3 years ago
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