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Alekssandra [29.7K]
3 years ago
10

A 100 watt incandescent light bulb is operated for 7 hours, and a 32 watt fluorescent light bulb is operated for the same period

of time. At 8 cents per kWh, what is the cost savings in using the fluorescent bulb?
Physics
1 answer:
Tema [17]3 years ago
4 0
<h2>Cost savings in using the fluorescent bulb is 3.81 cents</h2>

Explanation:

A 100 watt incandescent light bulb is operated for 7 hours.

Energy used by 100 watt incandescent light bulb = Power x Time

Energy used by 100 watt incandescent light bulb = 100 x 7 = 700 Wh

Energy used by 100 watt incandescent light bulb = 0.7 kWh

A 32 watt fluorescent light bulb is operated for 7 hours.

Energy used by 32 watt fluorescent light bulb = Power x Time

Energy used by 32 watt fluorescent light bulb = 32 x 7 = 224 Wh

Energy used by 32 watt fluorescent light bulb = 0.224 kWh

Cost of electricity per kWh = 8 cents

Cost of electricity by 100 watt incandescent light bulb = 0.7 x 8 = 5.6 cents

Cost of electricity by 32 watt fluorescent light bulb = 0.224 x 8 = 1.792 cents

Difference in costs = 5.6 - 1.792 = 3.808 cents

Cost savings in using the fluorescent bulb is 3.81 cents

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Furkat [3]

Answer:

Potential energy is U=mgh

Explanation:

The potential energy depends on the mass, the acceleration of gravity g and the height at which the object or person is.

Potential energy  U=mgh

In this case we would need to know the exact mass of the hiker in order to calculate the potential energy.

But we know the values of g and h

g=9.81m/s^2

h=60m

So, the potential energy

U=m(9.81m/s^2)(60m)\\\\U=588.6*m

m is the mass of the hiker, wich is not in the description of the problem.

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3 years ago
You want to slide a 0.39 kg book across a table. If the coefficient of kinetic friction is .21, what force is required to move t
uranmaximum [27]
Find the force that would be required in the absence of friction first, then calculate the force of friction and add them together.  This is done because the friction force is going to have to be compensated for.  We will need that much more force than we otherwise would to achieve the desired acceleration:

F_{NoFric}=ma=0.39kg \times0.18 \frac{m}{s^2}  =0.0702N

The friction force will be given by the normal force times the coefficient of friction.  Here the normal force is just its weight, mg

F_{Fric}=0.39kg \times 9.8 \frac{m}{s^2} \times 0.21=0.803N

Now the total force required is:

0.0702N+0.803N=0.873N

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3 years ago
How do you solve for frequency?
AleksAgata [21]

Answer:

frequency= 1/time period

5 0
3 years ago
What is disaster????​
telo118 [61]

<u>Disaster</u>:- a calamitous event, especially one occurring suddenly and causing great loss of life, damage, or hardship, as a flood / airplane crash.

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4 0
2 years ago
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What is the electric force acting between two charges of -0.0045 C and -0.0025 C that are 0.0060 m apart? Use Fe=kq1q2/r^2 and k
oksano4ka [1.4K]

Answer:

D. 2.8 × 10⁹ N

Explanation:

The force between two charges is directly proportional to the amount of charges at the two points and inversely proportional to the square of distance between the two points.

Fe= k Q₁Q₂/r²

Q₁= -0.0045 C

Q₂= -0.0025 C

r= 0.0060 m

k= 9.00 × 10 ⁹ Nm²/C²

Fe= (9.00 × 10 ⁹ Nm²/C²×-0.0045 C×-0.0025 C)/0.0060²

=2.8 × 10⁹ N

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3 years ago
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