First you must make sure all measurements are in the same value: You can choose either cm or km
Distance = 1,000,000 cm or 10 km
Radius = 50 cm or 0.0005 km
Distance/(2πR)
1,000,000/(2π*50)
1,000,000/314.059…….
Approx = 3183.1 Rotations
Answer:
Equation = X*(2/3) = 3/20
Solve for X = 0.23
Step-by-step explanation:
Let, the number be "X"
According to the question,
X*(2/3) = 3/20..........(i)
From equation (i), we can get,
X = (3/20)/(2/3)
or, X = 0.15/0.66
or, X = 0.23
Alternative way,
Let, the number be "X"
According to the question,
X*(2/3) = 3/20..........(i)
From equation (i), we can get,
X = (3/20)/(2/3)
or, X = (3/20)*(3/2)
or, X = 9/40
or, X = 0.23
Answer:
Step-by-step explanation:
<h3>A.</h3>
The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>
The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
Answer:
Step-by-step explanation:
Use these formulas
Now solve