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blsea [12.9K]
3 years ago
13

Simplify this expression. 2x/12(x + y)

Mathematics
2 answers:
Ymorist [56]3 years ago
5 0

Answer: = 1 /6 x^2+ 1 /6 xy

Step-by-step explanation:

yaroslaw [1]3 years ago
3 0
24 x2+24x y hope this helps
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What number should be placed in the box to help complete the division calculation. Pls help
ArbitrLikvidat [17]

Answer:

I believe it would be 4

3 0
3 years ago
Write the equation of the line that is parallel to y = -2x + 5 and goes through the point (4,-3).
kap26 [50]
Y = -2x + 5

All you have to do when coming across this type of problem is substitute x and y for the points given, as well as change whatever b is, in this case 5, for b. For example: -3 = -2(4) + b
7 0
4 years ago
24-10x=9<br> What does x equal to?
katrin [286]
X=1.5 also report other dude he put anything
6 0
3 years ago
Suppose that the functions p and q are defined as follows.
AlekseyPX
<u>Answer</u>
Part 1 = -441
Part 2 = -539

Explanation
(p.q)(5) = (-2x+1)(2x²-1)
             = (-2x×2x²)-(-2x×1)+(1×2x²)-(1×1)
             = -4x³+2x+2x²-1
             = -4x³+2x²+2x-1
Substituting x witj 5;
-4×5³+2×5²+2×5-1
-441

part 2
(q.p)(5) = (2x²-1)(-2x+1)
            = (2x²×-2x)-(2x²×1)-(1×-2x)+(1×1)
            =  -4x³-2x²+2x+1

Substituting x with 5;
-4×5³-2×5²+2×5+1
-539
4 0
3 years ago
Halloween Candy Halloween is Kelly's favorite holiday of the year! Based on experience, Kelly knows that on average, each house
LuckyWell [14K]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is an approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.

Normal Probability Distribution

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for n instances of a normal variable, the mean is n\mu while the standard deviation is s = \sigma\sqrt{n}.

In this problem:

  • Mean of 4 candies, hence \mu = 4.
  • Standard deviation of 1.5 candies, hence \sigma = 1.5.
  • She visited 35 houses, hence n = 35, \mu = 35(4) = 140, s = 1.5\sqrt{4} = 3

The probability is the <u>p-value of Z when X = 122</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{122 - 140}{3}

Z = -6

Z = -6 has a p-value of 0.

Approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.

A similar problem is given at brainly.com/question/24663213

6 0
3 years ago
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