Answer:
x=(10-k)÷6
Step-by-step explanation:
6x=10-k
x=(10-k)÷6
Step 1: Simplify both sides of the equation.
3(x−5)−5=23
(3)(x)+(3)(−5)+−5=23(Distribute)
3x+−15+−5=23
(3x)+(−15+−5)=23(Combine Like Terms)
3x+−20=23
3x−20=23
Step 2: Add 20 to both sides.
3x−20+20=23+20
3x=43
Step 3: Divide both sides by 3.
3x
/3 = 43
/3
x=
43
/3
Hello from MrBillDoesMath!
Answer:
The fourth choice, b = +\- sqrt( sg + a^2)
Discussion:
s = (b^2 - a^2)/g => multiply both sides by "g"
sg = b^2 - a^2 => add a^2 to both sides
sg + a^2 = b^2 => take the square root of each side
b = +\- sqrt( sg + a^2)
which is the fourth choice.
Thank you,
MrB
Hello once again!
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
Answer:
184 cm²
Step-by-step explanation:
Surface area of the rectangular box is expressed as S = 2(LW+LH+WH)
L is the length of the box = 90 cm
W is the width of the box = 50 cm
H is the height of the box= 90 cm
If there are error of at most 0.2 cm in each measurement, then the total surface area using differential estimate will be expressed as shown;
S = 2{(LdW+WdL) + (LdH+HdL) + (WdH+HdW)
Note that dL = dW = dH = 0.2 cm
Substituting the given values into the formula to estimate the maximum error in calculating the surface area of the box
S = 2{(90(0.2)+50(0.2)) + (90(0.2)+90(0.2)) + (50(0.2)+90(0.2))
S = 2{18+10+18+18+10+18}
S = 2(92)
S = 184 cm²
Hence, the maximum error in calculating the surface area of the box is 184cm²