Let's call the consecutive integers a, a+1, and a+2. they add up to 138: a+(a+1)+(a+2)=3a+3=138 now you have an equation: 3a+3=138 subtract 3 from both sides: 3a=135 divide both sides by 3: a=45 so the consecutive integers are 45, 46, and 47
If the integers were all the same, then each one would be 1/3 of 138 = 46 .
They're not all the same, but they're consecutive, so you can find them easily. Just start with your 3 copies of 46, take ' 1' away from one copy, and add it to another one. You haven't changed their sum. You just made one of your copies 1 less than 46, and you made another one of them 1 more than 46. Now you have 45, 46, and 47, and that sure looks like an answer to me. Isn't that easy ... you only had to use some brain instead of a lot of messy algebra. That's what 'Brainly' might be all about, I guess.
