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IceJOKER [234]
3 years ago
13

Helpp

Chemistry
2 answers:
Vlad1618 [11]3 years ago
4 0
I believe the answer would be solid to gas.
Alexeev081 [22]3 years ago
3 0
The answer is D. Liquid to Solid
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If the two atoms participating in a bond have an electron negativity difference of 1.9 , what type of of bond would they be part
brilliants [131]

Answer:

Polar covalent bond.

Explanation:

When the bond is formed between the atoms by sharing the electrons the bond thus have covalent character.   The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.  When the electronegativity difference is less than 0.4 the bond is non polar covalent.

When bonded atoms have greater electronegativity difference i.e 2 or greater than two the bond is ionic because electron is transfer from low electronegative atom to highest electronegative atom.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

In case of H₂, Cl₂, Br₂ the bond has very high covalent character because of zero electronegativity difference.

7 0
3 years ago
I NEED HELP ASAPPPPPPPPPPPPPPPP
RoseWind [281]

Answer:

i wold think it is C

Explanation:

8 0
2 years ago
Read 2 more answers
What did you observe about the properties of the sodium carbonate mixture before the substances were mixed together?
anzhelika [568]

Answer:

Would you consider adding a sodium carbonate solution to a magnesium sulfate .

Explanation:

??

5 0
2 years ago
In an inverse relationship, when one variable increases, the other____
Harrizon [31]

Answer: D

Explanation:

In an inverse relationship as one increases one decreases or vice versa.

7 0
3 years ago
Balance the following half-reaction: (acidic) NO−3(aq) → NO2(aq) Express your answer as a half-reaction. Identify all of the pha
Marrrta [24]

Answer:

2H⁺  + NO₃⁻  + 1e⁻ →  NO₂  + H₂O

Explanation:

NO₃⁻  →  NO₂

In left side, Nitrogen acts with +5 by oxidation number

In right side, the oxidation number is +4

This is a reduction reaction, because the oxidation number has decreased. So the N has gained electrons.

NO₃⁻  + 1e⁻ →  NO₂

In acidic medium, we have to add water, where there are less oxygens to ballance the amount. We have 2 O in left side, and 3 O in right side, so we have to add 1 H₂O on left side.

NO₃⁻  + 1e⁻ →  NO₂  + H₂O

Now that oxygens are ballanced, we have to ballance the hydrogens by adding protons in the opposite side

2H⁺  + NO₃⁻  + 1e⁻ →  NO₂  + H₂O

8 0
3 years ago
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