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3 years ago

Helpp

Chemistry

2 answers:

Vlad1618 [11]3 years ago

4 0

I believe the answer would be solid to gas.

Alexeev081 [22]3 years ago

3 0

The answer is D. Liquid to Solid

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Calculate the % dissociation of 0.10 M solution of acetic acid (pKa = 4.75)

madreJ [45]

Given :

Molarity of acetic acid solution, M = 0.10 M.

pKa of acetic acid, pKa = 4.75 .

To Find :

Percentage dissociation of 0.10 M solution of acetic acid.

Solution :

We know, $pK_a = -log\ K_a$

Taking antilog both side, we get :

$K_a = 1.78\times 10^{-5}$

Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.

Now, percentage dissociation of monoprotic acid is given by :

$\alpha = \sqrt{\dfrac{K_a}{C}}\\\\\alpha =\sqrt{ \dfrac{1.78\times 10^{-5}}{0.1}}\\\\\alpha = 0.0133\times 100 = 1.33 \%$

Hence, this is the required solution.

3 0

3 years ago

Consider the reaction between HCl and O2: 4HCl(g)+O2(g)→2H2O(l)+2Cl2(g) When 63.1 g of HCl is allowed to react with 17.2 g of O2

alina1380 [7]

Answer:

The limiting reactant for this reaction is the HCl

Explanation:

This is my reaction:

4HCl(g)+O2(g)→2H2O(l)+2Cl2(g)

Molar mass O2 = 32 g/mol

Molar mass HCl = 36,45 g/mol

Mass / Molar mass = Moles

Moles HCl : 63,1 g / 36,45 g/m = 1,73 moles

Moles O2: 17,2 g / 32g/m = 0,54 moles

4 moles of HCl react with 1 mol of O2, according to reaction, so

1,73 moles of HCl, are going to react with, how many moles of O2.

4 moles HCl ___ 1 mol O2

1,73 moles HCl ___ (1,73 . 1)/ 4 = 0,43 moles of O2

O2 is my excess reagent because I need 0,43 moles and I have 0,54 so I have moles in excess.

1 mol of O2 are going to react with 4 moles of HCl

0,54 moles of O2 are going to react with, how many moles of HCl ?

1 mol O2 ____ 4 moles HCl

0,54 mol O2 ___ (0,54 . 4)/ 1 = 2,16 moles

I need 2,16 moles to consume my moles of O2, but I only have 1,73 moles, tha's why the HCl is mi limiting reactant.

3 0

3 years ago

7. Which motion causes night and day on Earth? *

xeze [42]

Option B is the correct answer

7 0

4 years ago

1) If 0.193 grams of toluene is dissolved in 2.532 grams of p-xylene, what is the molality of toluene in the solution?2) If a fr

AveGali [126]

Answer:

The value of $K_f$ for xylene is 4.309°C/m.

The molar mass of pentane using this data is 73.82 g/mol.

Explanation:

$\Delta T_f=K_f\times \frac{\text{Amount of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent(kg)}}$

where,

$\Delta T_f$ =depression in freezing point

$K_f$ = freezing point constant

we have :

1) freezing point constant for xylene = $K_f$ =?

Mass of toluene = 0.193 g

Mass of xylene = 2.532 kg = 0.002532 kg ( 1 g =0.001 kg)

$\Delta T_f=3.57^oC$

$3.57^oC=K_f\times \frac{0.193 g}{92 g/mol\times 0.002532 kg}$

$K_f=4.309^oC/m$

The value of $K_f$ for xylene is 4.309°C/m.

Mass of pentane = 0.123 g

molar mass of pentame= M

Mass of xylene = 2.493 g = 0.002493 kg

Freezing point Constant of xylene = $K_f=4.309^oC/m$

$2.88^oC=4.309^oC/m\times \frac{0.123g}{M\times 0.002493 kg}$

M = 73.82 g/mol

The molar mass of pentane using this data is 73.82 g/mol.

5 0

3 years ago

How many TOTAL ELECTRONS are in the compound CO2?

Liula [17]

Answer:

22 electrons are in the compound CO2. And the correct answer is Phosphorus tribromide.

Explanation:

7 0

3 years ago