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Anna71 [15]
3 years ago
13

Pls help me with this I will give you brain

Chemistry
2 answers:
daser333 [38]3 years ago
7 0

Answer: temperate grasslands if wrong sorry

Explanation:

Vikentia [17]3 years ago
6 0

Answer:The answer would be chaparral.

Explanation:

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Can you tell me about atoms
trasher [3.6K]

Answer:

is the smallest unit of ordinary matter that forms a chemical element.

Explanation:

and were created after the Big Bang 13.7 billion years ago.

4 0
3 years ago
Nvm i have to answer lol
DIA [1.3K]

Answer:

i will do a joke... hmmm...

Explanation:

why did the nurse need a red pen?

To draw out blood. lol

5 0
2 years ago
Read 2 more answers
Compute 4.659×104−2.14×104. Round the answer appropriately.
IrinaK [193]
<span>To compute 4.659×104−2.14×104, the first step is the factorization. That is as follows:4.659×104−2.14×104= 10^4.(4.659−2.14), the next step is to compute 4.659−2.14=2.51, so 10^4.(4.659−2.14)=2.51x10^4=2.51x 10000 (because10^4=10000), the last calculus is 2.51x 10000=25100, the final answer is 25,000.Hope this helps. Let me know if you need additional help!</span>
7 0
3 years ago
Read 2 more answers
Given the following balanced equation:
svetlana [45]
So you would just take the coefficient and put it into ratio form

Answers:
1) 4:5
2)4:6
3)6:4
4)6:6
5)6:4
3 0
2 years ago
An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f
Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

  • Mass of carbon, C:

\frac{32.18}{100}\times 223.94 = 72.06 g

  • Mass of hydrogen, H:

\frac{4.5}{100}\times 223.94 = 10.08 g

  • Mass of chlorine, Cl:

\frac{63.32}{100}\times 223.94 = 141.79 g

Now, the number of each element in the unknown compound is determined by the formula:

number of moles = \frac{given mass}{molar mass}

  • Number of moles of C:

number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole

  • Number of moles of H:

number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole

  • Number of moles of Cl

number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole

Dividing each mole with the smallest number of mole, to determine the empirical formula:

C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}

C_{1.5}H_{2.5}Cl_{1}

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is C_{3}H_{5}Cl_{2}.

Empirical mass = 12\times 3+1\times 5+2\times 35.5 = 112 g/mol

In order to determine the molecular formula:

n = \frac{molar mass}{empirical mass}

n = \frac{223.94}{112} = 1.99 \simeq 2

So, the molecular formula is:

2\times C_{3}H_{5}Cl_{2} =  C_{6}H_{10}Cl_{4}

6 0
3 years ago
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