Answer: B
Explanation: im pretty sure my teacher mentioned something about N--h bonds are non polar
Using the atomic weights, K = 39, O=16 so KO2= 39+32=71. So K=39/71= 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2= 9.76+8g=17.76.
Answer:
Kf = 9.96x10⁴¹
Explanation:
When Fe³⁺ and CN⁻ are in water, complex Fe(CN)₆³⁻ is formed, thus:
Fe³⁺ + 6CN⁻ ⇄ Fe(CN)₆³⁻
Kf is defined as:
Kf = [Fe(CN)₆³⁻] / [Fe³⁺] [CN⁻]⁶
Equilibrium concentration of ions is:
[Fe(CN)₆³⁻] = 1.5x10⁻³M
[Fe³⁺] = 8.5x10⁻⁴⁰
[CN⁻] = [KCN] = 0.11M
Replacing in Kf expression:
Kf = [1.5x10⁻³M] / [8.5x10⁻⁴⁰] [ 0.11M]⁶
<h3>Kf = 9.96x10⁴¹</h3>
Answer:
A cold front is a boundary or zone that separates two air masses. The cooler more dense mass replaces the warmer.
hope this helps :)
Explanation:
