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Nina [5.8K]
3 years ago
9

Newton’s third law of motion explains the two forces namely ‘action’ and ‘reaction’ coming into action when the two bodies are i

n contact with each other. These two forces: *
(a) Always act on the same body
(b) Always act on the different bodies in opposite directions
(c) Have same magnitude and direction
(d) Acts on either body at normal to each other
Pls fast
Physics
2 answers:
IRISSAK [1]3 years ago
8 0

Answer:

b) Always act on the different bodies in opposite directions

Explanation:

b) Always act on the different bodies in opposite directions

For example:

If I am sitting on a sofa and I exert 370N and the sofa will exert -370N force. If the sofa doesn't exert force back, I won't be able to sit which means it will break.

Hope it helps ;) ❤❤❤

SIZIF [17.4K]3 years ago
7 0

(b) Always act on the different bodies in opposite directions

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6 0
3 years ago
What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2400 kg car (a large car
makvit [3.9K]

Answer:

Fm= 91.88 N

Explanation:

Pascal principle

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

The pressure is definited like this:

P=F/A

Where:

P: Pressure in pascals (Pa)

F: Force acting in the area  (N)

A  : Area where the force acts  (m²)

Pascal principle

Pm=Ps

Fm/ Am= Fs/ As  Formula (1)

Where :

Pm : Pressure on the master piston

Ps  : Pressure on the slave piston

Fm : Force on the master piston (N)

Fs:  Force on the  slave piston ((N)

Am: master piston area (m²)

As:  slave piston area  (m²)

Area Formula (A)

A= π*R²

R : piston radius

Calculation of the weight of the car (W)

W= m*g= 2400 kg*9.8m/s²= 23520 N

W = Fs

Data

Fs =  23520 N

Dm = 1.5 cm

Ds = 24 cm

Rm = 0.75 cm

Rs = 12 cm

Am = π*Rm² = π*(0.75)²

As = π*Rs² = π*(12)²

Force exerted on the master cylinder

We replace data in the formula (1)

\frac{F_{m} }{A_{m} } = \frac{F_{s} }{A_{s} }

F_{m}  = \frac{F_{s}*A_{m}  }{A_{s}}

F_{m} = \frac{(23520 N)*(\pi *(0.75)^{2})(cm^{2})}{(\pi *(12)^{2})(cm^{2})}

F_{m} = (23520 N)*\frac{(0.75)^{2} }{(12)^{2} }

Fm= 91.88 N

8 0
3 years ago
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