Question

19 point please please answer right need help

Answer 1

Explanation:

We can write Newton's 2nd law as applied to the sliding mass $m_1$ as

$T - m_1g\sin38 = m_1a\:\:\:\:\:\:\:(1)$

For the hanging mass $m_2,$ we can write NSL as

$T - m_2g = -m_2a\:\:\:\:\:\:\:(2)$

We need to solve for a first before we can solve the tension T. So combining Eqns(1) & (2), we get

$(m_1 + m_2)a = m_2g - m_1g\sin38$

or

$a = \left(\dfrac{m_2 - m_1\sin38}{m_1 + m_2}\right)g$

$\:\:\:\:= 0.30\:\text{m/s}^2$

Using this value for the acceleration on Eqn(2), we find that the tension T is

$T = m_2(g - a) = (2.6\:\text{kg})(9.51\:\text{m/s}^2)$

$\:\:\:\:=24.7\:\text{N}$