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3 years ago

19 point please please answer right need help

Physics

1 answer:

dimulka [17.4K]3 years ago

6 0

Explanation:

We can write Newton's 2nd law as applied to the sliding mass $m_1$ as

$T - m_1g\sin38 = m_1a\:\:\:\:\:\:\:(1)$

For the hanging mass $m_2,$ we can write NSL as

$T - m_2g = -m_2a\:\:\:\:\:\:\:(2)$

We need to solve for a first before we can solve the tension T. So combining Eqns(1) & (2), we get

$(m_1 + m_2)a = m_2g - m_1g\sin38$

$a = \left(\dfrac{m_2 - m_1\sin38}{m_1 + m_2}\right)g$

$\:\:\:\:= 0.30\:\text{m/s}^2$

Using this value for the acceleration on Eqn(2), we find that the tension T is

$T = m_2(g - a) = (2.6\:\text{kg})(9.51\:\text{m/s}^2)$

$\:\:\:\:=24.7\:\text{N}$

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Answer:

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Explanation:

Given data:

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$P_2 = 80 kPa$

Polytropic exponent n = 1.4

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putting all value

$\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}$

$\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS$

polytropic process is given as

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$150\times 0.08^{1.4} = 80 \times V_2^{1.4}$

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4 0

3 years ago

A girl throws a rock horizontally at 10 m/s from the top of a building, 22 m above street level. Assuming free fall conditions a

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Answer:21.18 m

Explanation:

Given

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$h=ut+\frac{1}{2}at^2$

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$22=\frac{1}{2}gt^2$

$t=\sqrt{\frac{22\times 2}{g}}$

$t=2.11 s$

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3 years ago

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Answer:

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Explanation:

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v² = v₀² - 2 a x

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a = v₀² / 2x

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3 years ago

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