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denis23 [38]
2 years ago
6

19 point please please answer right need help

Physics
1 answer:
dimulka [17.4K]2 years ago
6 0

Explanation:

We can write Newton's 2nd law as applied to the sliding mass m_1 as

T - m_1g\sin38 = m_1a\:\:\:\:\:\:\:(1)

For the hanging mass m_2, we can write NSL as

T - m_2g = -m_2a\:\:\:\:\:\:\:(2)

We need to solve for a first before we can solve the tension T. So combining Eqns(1) & (2), we get

(m_1 + m_2)a = m_2g - m_1g\sin38

or

a = \left(\dfrac{m_2 - m_1\sin38}{m_1 + m_2}\right)g

\:\:\:\:= 0.30\:\text{m/s}^2

Using this value for the acceleration on Eqn(2), we find that the tension T is

T = m_2(g - a) = (2.6\:\text{kg})(9.51\:\text{m/s}^2)

\:\:\:\:=24.7\:\text{N}

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When is the magnitude of the acceleration of a mass on a spring at its maximum value?
Andreas93 [3]

Answer:

A. when the mass has a speed of zero

Explanation:

In mass-spring system, the velocity and the acceleration are in anti-phase, which means that when one of the two quantities is maximum, the other one is zero, and vice-versa.

In fact:

- When the displacement of the spring is zero (x=0), the velocity is maximum, due to conservation of energy. In fact, as the displacement is zero, the elastic potential energy of the system (given by \frac{1}{2}kx^2) is zero, therefore the kinetic energy (given by \frac{1}{2}mv^2) must be maximum, and so the velocity (v) is also maximum. On the cotnrary, acceleration (a) is directly proportional to the restoring force of the spring, given by

F=-kx

so we see that when x=0, then the force is zero: F=0, and so the acceleration is zero as well.

- When the displacement of the spring is maximum, the velocity is zero, due to conservation of energy. In fact, as the displacement is maximum, the elastic potential energy of the system (given by \frac{1}{2}kx^2) is maximum, therefore the kinetic energy (given by \frac{1}{2}mv^2) must be zero, and so the velocity (v) is also zero. On the cotnrary, since acceleration (a) is directly proportional to the restoring force of the spring, given by

F=-kx

so we see that when x=maximum, then the force is maximum, and so the acceleration is maximum as well.

Based on this, the correct answer is

A. when the mass has a speed of zero


5 0
2 years ago
Read 2 more answers
A block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so that the
bezimeni [28]

Answer:

The answer is "a, c and b"

Explanation:

  • Its total block power is equal to the amount of potential energy and kinetic energy.
  • Because the original block expansion in all situations will be the same, its potential power in all cases is the same.
  • Because the block in the first case has no initial speed, the block has zero film energy.
  • For both the second example, it also has the v_o velocity, but the kinetic energy is higher among the three because its potential and kinetic energy are higher.
  • While over the last case the kinetic speed is greater and lower than in the first case, the total energy is also higher than the first lower than that of the second.
  • The greater the amplitude was its greater the total energy, therefore lower the second, during the first case the higher the amplitude.
4 0
2 years ago
A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the end of the
Strike441 [17]

Answer:

c. 2 m/s

Explanation:

The relationship between speed, frequency and wavelength of a wave is given by:

v=f \lambda

where

v is the speed of the wave

f is its frequency

\lambda is the wavelength

For the transverse wave in this problem, we have:

f = 4 Hz is the frequency

\lambda=0.5 m is the wavelength

Substituting these numbers into the equation, we find the speed of the wave:

v=(4 Hz)(0.5 m)=2 m/s

7 0
3 years ago
Free point cuz i cewl like dat‍♀️‍♂️
DedPeter [7]
Yes thank u teehee




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2 years ago
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Round your answers to one decimal place.this parallel circuit has two resistors at 15 and 40 ohms. what is the total resistance?
lubasha [3.4K]
1) The equivalent resistance of two resistors in parallel is given by:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}
so in our problem we have
\frac{1}{R_{eq}} =  \frac{1}{15 \Omega}+ \frac{1}{40 \Omega}=0.092 \Omega^{-1}
and the equivalent resistance is
R_{eq} =  \frac{1}{0.092 \Omega^{-1}}=10.9 \Omega

2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
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