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denis23 [38]
3 years ago
6

19 point please please answer right need help

Physics
1 answer:
dimulka [17.4K]3 years ago
6 0

Explanation:

We can write Newton's 2nd law as applied to the sliding mass m_1 as

T - m_1g\sin38 = m_1a\:\:\:\:\:\:\:(1)

For the hanging mass m_2, we can write NSL as

T - m_2g = -m_2a\:\:\:\:\:\:\:(2)

We need to solve for a first before we can solve the tension T. So combining Eqns(1) & (2), we get

(m_1 + m_2)a = m_2g - m_1g\sin38

or

a = \left(\dfrac{m_2 - m_1\sin38}{m_1 + m_2}\right)g

\:\:\:\:= 0.30\:\text{m/s}^2

Using this value for the acceleration on Eqn(2), we find that the tension T is

T = m_2(g - a) = (2.6\:\text{kg})(9.51\:\text{m/s}^2)

\:\:\:\:=24.7\:\text{N}

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 I will mark you as brainliest if you answer correctly
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V=IR
where
V is the potential difference across the electrical device
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R= \rho \frac{L}{A}
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