A current-carrying wire of length 52.0 cm is positioned perpendicular to a uniform magnetic field. If the current is 15.0 A and
1 answer:
Answer:
The magnetic field strength is 0.29 T.
Explanation:
Given that,
Length of current-carrying wire, L = 52 cm = 0.52 m
Current, I = 15 A
Magnetic force, F = 2.3 N
We need to find the magnetic field strength. We know that the magnetic force is given by :
B is magnetic field strength
So, the magnetic field strength is 0.29 T.
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Answer:
A) 1.67 x 10 ⁻⁶ m/s
B)5.59 x %
Explanation:
A)
Given:
d = 5.0 km,
mₐ = 2.5 x kg
u₁ = 4.0 x 10⁴ m/s
= 5.98 x 10 ²⁴ kg
Solve using kinetic conserved energy
mₐ x u₁ + x u₂ = uₓ x (mₐ +
)
(2.5 x ) (4.0 x 10⁴ )+ (5.98 x 10 ²⁴ )(0) = uₓ x (2.5 x
+ 5.98 x 10 ²⁴ )
uₓ = ( 2.5 x x 4.0 x 10⁴ ) / (2.5 x
+ 5.98 x 10 ²⁴ )
uₓ = 1.67 x 10 ⁻⁶ m/s
B) Assuming earth radius as a R = 1.5 x 10 ¹¹ m
t = 365 days x 24 hr / 1 day x 60 minute / 1 hr x 60s / 1 minute = 31536000 s
t = 31536000 s
D = 2 π R = 2 π( 1.5 x 10 ¹¹ )
D = 9.4247 x 10 ¹¹ m
u₂ = D / t = 9.4247 x 10 ¹¹ / 31536000
u₂ = 29885.775 m/s
% = ( 1.67 x 10 ⁻⁶ m/s ) / (29885.775 m/s) x 100
% = 5.59 x %