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Setler79 [48]
3 years ago
7

Help or else i’ll fail

Mathematics
1 answer:
Georgia [21]3 years ago
8 0
The answer is equilateral
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15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h
alina1380 [7]

Answer:(g,h)=(-2,2)

Step-by-step explanation:

Given

Midpoint is (-2,3)

Endpoints are G(g,4) and H(-2,h)

Mid point of any two point is given by

x=\frac{x_1+x_2}{2}

and y=\frac{y_1+y_2}{2}

So,-2=\frac{g+(-2)}{2}

-4=g-2

g=-2

Also

3=\frac{4+h}{2}

6=4+h

h=2

Therefore (g,h)=(-2,2)

4 0
3 years ago
Y = x + 5<br> 2x + y = 17
larisa [96]

Answer:

y = x + 5: x=y−5

2x + y = 17 : x=-1/2y+17/2

Step-by-step explanation:

I do not exactly know what you were asking but I just answered the questions, if that is not what you were looking for tell me so I can try and edit my answer

8 0
2 years ago
Two trains leave the station at the same time, one heading west and the other east. The westbound train travels at 95 miles per
Ludmilka [50]

Answer:

2.2 hr

Step-by-step explanation:

Let t = time

95t = distance of westbound train

105t = distance of eastbound train

95t + 105t = 440

200t = 440

t = 2.2 hr.

8 0
3 years ago
What is the best measure of center for this data set?
jenyasd209 [6]
I believe the answer to your question is b.
3 0
2 years ago
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