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ExtremeBDS [4]
3 years ago
14

Type the correct answer in the box. The pressure inside a tire is measured as 28.0 . What is its pressure in ? 1 pound = 4.45 ne

wtons 1 inch2 = 6.45 centimeters2 Express the answer to the correct number of significant figures. The pressure is .
Chemistry
1 answer:
posledela3 years ago
8 0

The pressure is 19.3 N/cm².

<em>p</em> = (28.0 lb/1 in²) × (4.45 N/1 lb) × (1 in²/6.45 cm²) = 19.3 N/cm²

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The scientific notation 2 x 10-2 has what value? <br> 0.02<br> 0.002<br> 0.2<br> 0.0002
Marta_Voda [28]
Since the exponent is negative, you move the decimal (2.0) to the left two spots leaving you with .02
7 0
2 years ago
Read 2 more answers
Pulses A, B, C, and D all travel at 10 m/s on the same string but in opposite directions. The string is depicted at time t=0 in
Anit [1.1K]

(a) The displacement of point P at time t=0.10s is determined as +2cm.

(b) The displacement of point P at time t=0.20s is determined as -2cm.

<h3>What is displacement?</h3>

Displacement is the change in position of an object. It is obtained from the product of velocity and time of motion.

x = vt

<h3>Displacement of the waves after 0.1 s</h3>

x = 10 m/s x 0.1 s = 1 m

Each wave will travel 1 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 0 m
  • wave A from left will stop at point -1 m
  • wave C from right will stop at point 0 m
  • wave D from right will stop at point + 1 m

wave B and C superimposed and the displacement will be between A and D.

Amplitude of A = - 2cm

Amplitude of D = + 4cm

Displacement of point P = 4 cm - 2 cm =  2cm

<h3>Displacement of the waves after 0.2 s</h3>

x = 10 m/s x 0.1 s = 2 m

Each wave will travel 2 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 1 m
  • wave A from left will stop at point 0 m
  • wave C from right will stop at point -1 m
  • wave D from right will stop at point 0 m

Displacement of point P = (amplitude B + amplitude C) + (amplitude A + amplitude D)

Displacement of point P= (2cm - 2cm) + (2 cm - 4cm)= -2cm

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

8 0
2 years ago
What is the atomic number of the element located in group 16
laila [671]

Answer:

Sulfur

Explanation:

Sulfur is a chemical element that is represented with the chemical symbol "S" and the atomic number 16 on the periodic table.

7 0
2 years ago
A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, c
natka813 [3]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

  • Ca: 40.078.

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

  • The mass of one mole of CaCO₃ is the same as the molar mass of this compound: \rm 100\; g.
  • The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: \rm 40.078\; g.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}.

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be \rm 30 \% \times 100\; g = 30\; g of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio \displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}:

\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}.

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%.

3 0
2 years ago
A 4.5 M solution is to be diluted to 750.0 mL of a 1.5 M solution. How many mL of the 4.500 M solution are required?
maw [93]

Answer:

309

Explanation:

7 0
2 years ago
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