Answer:
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Explanation:
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The ratio of effusion rates for the lightest gas H₂ to the heaviest known gas UF₆ is 13.21 to 1
<h3>What is effusion?</h3>
Effusion is a process by which a gas escapes from its container through a tiny hole into evacuated space.
Rate of effusion ∝ 1/√Ц, (where Ц is molar mass)
Rate H₂ = 1/√ЦH₂
Rate UF₆ = 1/√ЦUF₆
Therefore, Rate H₂/ Rate UF₆ = √ЦH₂/√ЦUF₆
ЦH₂= 2.016 g/mol
ЦUF₆= 352.04 g/mol
Rate H₂ / Rate UF₆ = √352.04/√2.016 = 18.76/1.42
Rate H₂ / Rate UF₆ = 13.21
Therefore, H₂ is lower mass than UF₆. Thus H₂ gas will effuse 13 times more faster than UF₆ because the most probable speed of H₂ molecule is higher; therefore, more molecules escapes per unit time.
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Answer: Millard Reaction
Explanation:The yummy process, called the Maillard reaction, packs the cookie with riche taste
1) Write the balanced chemical equation:
2Al + 6HCl ---> 2AlCl3 + 3H2
2) Calculate the molar masses of Al and HCl and use them to convert the data to moles
Al: 27g/mol => 10.7 gAl / 27g/mol = 0.396 mol Al
HCl: 1g/mol + 35.5 g/mol = 36.5g/mol => 42.5gHCl / 36.5g/mol = 1.164 mol HCl
Theoretical ratio: 6 mol HCl / 2 mol Al = 3:1
Actual ratio: 1.164 mol HCl / 0.396 mol Al = 2.94 : 1
Then there is a little bit less HCl than the predicted by theoretical ratio, which means that this is the limitant reagent.
3) Use the amount of HCl to make the calculations of the proucts obtained.
Theoretical ratio: 3 mol H2 / 6 mol HCl = 1:3
1.164 mol HCl * 1 mol H2 / 3 mol HCl = 0.388 mol H2
4) Use the ideal gas formula to obtain the volume
pV = n RT
p = 725 mmHg * 1atm / 760mmHg = 0.954 atm
n = 0.388 mol
R = 0.082 atm*liter /K*mol
T = 47 °C + 273.15 = 320.15K
V = nRT/p = 0.388 mol * 0.082 [atm*liter/K*mol] * 320.15K / 0.954 atm = 10.7 liter
Answer: 10.7 liter
