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3 years ago

An SO2 sample occupies a volume of 60 ml at 318 K. At what temperature will the gas occupy a volume of 180 ml?

Chemistry

1 answer:

algol [13]3 years ago

8 0

Answer:

THE TEMPERATURE OF THE GAS AT 180 mL IS 957 K

Explanation:

This question follows Charles' law of the theory of gases. it states that the volume of a fixed mass of gas varies directly with the absolute temperature provided the pressure remains constant.

Mathematically, V1 /T1 = V2 /T2

V1 = 60 mL = 60 /1000 L = 0.06 L

T1 = 319 K

V2 = 180 mL = 180 /1000 L = 1.80 L

T2 = ?

Making T2 the subject of the formula, we have;

T2 = V2 * T1 / V1

T2 = 0.180 * 319 / 0.06

T2 = 57. 42 / 0.06

T2 = 957 K

So therefore, the temperature of the gas at a new volume of 180 mL is 957 K

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3 years ago

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Answer:

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Explanation:

Given that,

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Yakvenalex [24]

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2 years ago

An archaeologist graduate student found a leg bone of a large animal during the building of a new science building. The bone had

Vlad [161]

Answer : The time passed in years is $2.74\times 10^2\text{ years}$

Explanation :

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First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5730\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

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k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = initial amount of the reactant disintegrate = 15.3

a - x = amount left after decay process = 14.8

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{15.3}{14.8}$

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4 0

3 years ago

Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.

qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

c= 4.184 $\frac{J}{g*C}$
m= 32 g
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Replacing:

Q= 32 g* 4.184 $\frac{J}{g*C}$ *14 °C

Solving:

Q= 1,874.432 J

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

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2 years ago