Answer:
The substance that remained on the filter paper is Al(OH).
Explanation:
- Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
- So in our experiment the product formed is aluminum hydroxide Al(OH) and sodium chloride (NaCl).
- Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
- Hence aluminum hydroxide being only solid product remains on the filter paper.
The answer is A, biogeochemical cycles.
The answer is true, particles in the gaseous state are the furthest apart
<span>1.44x10^23 molecules of oxygen gas
The ideal gas law is
PV = nRT
where
P = pressure (800.0 Torr)
V = volume (5.60 L)
n = number of moles
R = Ideal gas constant (62.363577 L*Torr/(K*mol) )
T = absolute temperature (27C + 273.15 = 300.15 K)
Let's solve for n, the substitute the known values and solve.
PV = nRT
PV/RT = n
(800.0 Torr*5.60 L)/(62.363577 L*Torr/(K*mol)*300.15 K) = n
(4480 L*Torr)/(18718.42764 L*Torr/mol) = n
0.239336342 mol = n
So we have 0.239336342 moles of oxygen molecules. To get the number of atoms, we need to multiply by avogadro's number, so:
0.239336342 * 6.0221409x10^23 = 1.44x10^23</span>
Answer : Group 14 elements are likely to have substances that have both metal and non-metallic properties.
Explanation :
Metalloid : It is a type of element whose properties lies in between the metals and non-metals.
There are commonly six metalloids : Boron(group 13), Silicon & Germanium(group 14), Arsenic & Antimony(group 15), Tellurium(group 16).
Properties of Metalloids :
- Metalloids look like metals but behave largely like non-metals.
- Metalloids are solid, brittle and lustrous.
- Metalloids has ability to conduct electricity.
Therefore, Group 14 elements are likely to have substances that have both metal and non-metallic properties.
