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Sloan [31]
3 years ago
11

Enter the number of electrons in each energy level (shell) for each of the elements. If the energy level does not contain any

Chemistry
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

ne=1s2,2s2,2p6,

ar=1s2,2s2,2p6,3s2,3p6

ca=1s2,2s2,2p6,3s2,3p6,4s2

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5 0
3 years ago
Read 2 more answers
Age
cupoosta [38]

Answer:

Option (2)

Explanation:

Since the amount of each sample is the same, we are looking for the metal with the greatest density, which is copper.

5 0
2 years ago
The number of ions in 17.1 gm of aluminum sulphate Al2 (SO4)3 =….. [Molar mass of Al2 (SO4)3 = 342 gm]
katen-ka-za [31]

Answer:

1.51 X 10^23 ions

Explanation:

The number of ions in 17.1 gm of aluminum sulphate Al2 (SO4)3 =….. [Molar mass of Al2 (SO4)3 = 342 gm]

in one molecule of Al2(SO4)3 there are 5 ions 2 aluminum and 3 sulfate ions

in 2 molecules there are 2X5= 10 ions

in 10 molecules there are 10X5 = 50 ions

molar mass of Al2(SO4)3 = (2 X 26.98) +( 3 X 32.1) + (3 X 4 X 16.0 ) =342.gms = 17.1/342 =0.0500 moles

1  mole =6.02 X 10^23 molecules ( see Avogadros number)

0.0500 moles = 0.0500 X 6.02 X 10^23 molecules =

0.301 X 10^23 molecules = 3.01 X 10^22 molecules

We determined that each molecule of Al2(SO4)3 has 5 ions

so 3.01 X10^22 molecules have 5 X 3.01 X 10^22 ions =

15.05 X 10^22 ions = 1.51 X 10^23 ions

3 0
3 years ago
What is the charge on an atom after it gains two electrons during the formation of a bond?
vekshin1

Answer:

two negative charges is the answer of your question

8 0
3 years ago
Write a nuclear equation to describe the spontaneous fission of 95 244 Am to form I-134 and Mo-107. Determine how many neutrons
MissTica

<u>Answer:</u> 3 neutrons are produced in the above nuclear reaction.

<u>Explanation:</u>

In a nuclear reaction, the total mass and total atomic number remains the same.

The nuclear reaction for the fission of Americium-244 isotope follows:

^{244}_{95}\textrm{Am}\rightarrow ^{134}_{53}\textrm{I}+^{107}_{42}\textrm{Mo}+Y^1_0\textrm{n}

<u>To calculate Y:</u>

Total mass on reactant side = total mass on product side

\Rightarrow 244=134+107+(Y\times 1)\\\\\Rightarrow Y=244-241=3

Hence, 3 neutrons are produced in the above nuclear reaction.

4 0
3 years ago
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