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3 years ago

Is the following statement true or false?

1 answer:

5 0

True because you can put it in any order without affecting it. Example : 5 • 7 = 7 • 5. Either way they still equal 35, therefore the answer will be true.

Hope this helps :)

You might be interested in

Write each polynomial in standard form. Then give the leading coefficient. You may need to combine like terms before writing the

Bond [772]

Step-by-step explanation:

To write a polynomial in standard form, put the degree that are the greatest first

So here it would be

${x}^{5} + 4 {x}^{3} - 3 {x}^{2} + 10$

Remember constant are numbers that you learned back in elementary,

Numbers like 10,90,4,1,0,-3 etc.

Remember that constant are basically represented like this

$k \times {x}^{0}$

For example, 10 is represented like

$10 \times {x}^{0}$

Since 0 is the smallest degree possible, for a polynomial, constants are the last term of a polynomial in standard form

6 0

2 years ago

Calculate the area and perimeter plz help

kramer

Answer:

Figure 1:

Area: 30m^2

Perimeter: 23.6m

Figure 2:

Area: 98.8km^2

Perimeter:56.5km

Step-by-step explanation:

Area is base x height.

To get the perimeter, add up all the sides.

Figure 1:

Area:

6x5=30m^2

Perimeter: 6+5.8+6+5.8=23.6m

Figure 2:

Area:

7.6x13 = 98.8km^2

Perimeter:7.6+15+20+13.9=56.5km

7 0

3 years ago

ILL MARK BRAINLIST IF ITS RIGHT.

erastovalidia [21]

Answer:

Step-by-step explanation:

The formula you should use is

b = 7 * h

You can try any value to see what happens

Let h = 3

b = 3*7

b = 21

3 0

3 years ago

Leo the Rabbit

Ghella [55]

23 I think idk I try

3 0

3 years ago

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

3 years ago