Answer:
4.924 years
Step-by-step explanation:
Lets denote X the lifetime of a tv tube (In years). X has distribution 
, with 
unknown.
We know that P(X < 4) = 0.2. Using this data, we can find the value of throught standarization.
Lets call 
the standarization of X. Z has distribution N(0,1), and its cummulative function, 
is tabulated. The values of can be found in the attached file.
The value q such that 
doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that 
, hence -q must be equal to 0.84. Thus, q = -0.84
But this value of q should match with the number 
, so we have
Thus, the expected lifetime of TV tubes is 4.924 years.
I hope this works for you!
The <span>statement correctly describes the key features of the graph of f(x) = − 4(one half)x + 1 − 3 </span>B) Y-intercept of (0, −5), starts down on the left, gets closer to y = −3 on the right. Hope that helps you.
Answer:
Area = y² + 2x + 1
Step-by-step explanation:
You have to combine like terms:
The little square is 1 unit, so 1
The two bars are each worth x, so 2 * x = 2x
The big square is y²
The total area is the sum of all terms:
Area = y² + 2x + 1
-Chetan K
